如何在sql中显示1行中的3行？

Question

我有1个问题在sql中

我该如何显示3行的行？

这里是我的SQL代码

SELECT jobcard.code AS code1,jobcard.name AS name1,nvl(masterpm.id,0)toal 
FROM jobcard 
    LEFT JOIN masterpm ON jobcard.id = masterpm.jobcard_id 
        and masterpm.id in (select masterpm_id from cbmmasterpm) 

和图像从选择结果

现在我怎么能显示3特里行1行代码，名称不得到重复一遍，我真的很需要那

Answer 1

如果你正在使用MySQL，你可以使用GROUP BY和GROUP_CONCAT所有TOAL值如：

SELECT jobcard.code AS code1,jobcard.name AS name1, GROUP_CONCAT(NVL(masterpm.id,0)) AS toal 
FROM jobcard LEFT JOIN masterpm ON jobcard.id = masterpm.jobcard_id AND masterpm.id in (SELECT masterpm_id FROM cbmmasterpm) 
GROUP BY code1, name1; 

Here's关于GROUP_CONCAT的MySQL文档。

更新

当你使用的是Oracle，你可以使用listagg函数来实现相同的功能，例如：

SELECT jobcard.code AS code1, jobcard.name AS name1, 
LISTAGG(NVL(masterpm.id,0), ', ') WITHIN GROUP (ORDER BY masterpm.id) "TOAL" 
FROM jobcard LEFT JOIN masterpm ON jobcard.id = masterpm.jobcard_id AND masterpm.id in (SELECT masterpm_id FROM cbmmasterpm) 
GROUP BY code1, name1; 

Here's的文档。