使用下面的代码,当输出到GUI中的标签时,变量(double)dAvgRun1,dAvgRun2(因此变量dBest)以NaN形式返回。Java计算双打 - NaN
我在做我的双打NaN的代码时犯了什么错误?
double [][] daRun = new double[2][7];
//Sets Athlete Name and Nationality labels to selected athlete in JList
jLabel_Athlete.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).sName);
jLabel_Country.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).sCountry);
//Returns all scores for selected athlete
jTextField_Run1_0.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun1[0]);
jTextField_Run1_1.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun1[1]);
jTextField_Run1_2.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun1[2]);
jTextField_Run1_3.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun1[3]);
jTextField_Run1_4.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun1[4]);
jTextField_Run1_5.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun1[5]);
jTextField_Run1_6.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun1[6]);
jTextField_Run2_0.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun2[0]);
jTextField_Run2_1.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun2[1]);
jTextField_Run2_2.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun2[2]);
jTextField_Run2_3.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun2[3]);
jTextField_Run2_4.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun2[4]);
jTextField_Run2_5.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun2[5]);
jTextField_Run2_6.setText(vecAthlete.get(jList_Athlete.getSelectedIndex()).saTempRun2[6]);
//Parse all scores from string to double
daRun[0][0] = Double.parseDouble(jTextField_Run1_0.getText());
daRun[0][1] = Double.parseDouble(jTextField_Run1_1.getText());
daRun[0][2] = Double.parseDouble(jTextField_Run1_2.getText());
daRun[0][3] = Double.parseDouble(jTextField_Run1_3.getText());
daRun[0][4] = Double.parseDouble(jTextField_Run1_4.getText());
daRun[0][5] = Double.parseDouble(jTextField_Run1_5.getText());
daRun[0][6] = Double.parseDouble(jTextField_Run1_6.getText());
daRun[1][0] = Double.parseDouble(jTextField_Run2_0.getText());
daRun[1][1] = Double.parseDouble(jTextField_Run2_1.getText());
daRun[1][2] = Double.parseDouble(jTextField_Run2_2.getText());
daRun[1][3] = Double.parseDouble(jTextField_Run2_3.getText());
daRun[1][4] = Double.parseDouble(jTextField_Run2_4.getText());
daRun[1][5] = Double.parseDouble(jTextField_Run2_5.getText());
daRun[1][6] = Double.parseDouble(jTextField_Run2_6.getText());
//Finds maximum and minimum scores for both runs
int z;
double dMinScoreRun1 = 10, dMaxScoreRun1 = 0;
double dMinScoreRun2 = 10, dMaxScoreRun2 = 0;
for (z=0; z<daRun.length; z++)
{
if (daRun[0][z] > dMaxScoreRun1)
{dMaxScoreRun1 = daRun[0][z];}
if (daRun[0][z] < dMinScoreRun1)
{dMinScoreRun1 = daRun[0][z];}
if (daRun[1][z] > dMaxScoreRun2)
{dMaxScoreRun2 = daRun[1][z];}
if (daRun[1][z] < dMinScoreRun2)
{dMinScoreRun2 = daRun[1][z];}
}
//Calculates average scores
double dTotalRun1 = 0, dTotalRun2 = 0;
double dAvgRun1 = 0, dAvgRun2 = 0;
//Run 1
for (z=0; z<daRun.length; z++)
{
if(daRun[0][z] == dMaxScoreRun1 || daRun[0][z] == dMinScoreRun1)
continue;
dTotalRun1 += daRun[0][z];
}
dAvgRun1 = dTotalRun1/(daRun.length-2);
//Run 2
for (z=0; z<daRun.length; z++)
{
if(daRun[1][z] == dMaxScoreRun2 || daRun[1][z] == dMinScoreRun2)
continue;
dTotalRun2 += daRun[1][z];
}
dAvgRun2 = dTotalRun2/(daRun.length-2);
//Displays averages for both runs
jLabel_Average1.setText(Double.toString(dAvgRun1));
jLabel_Average2.setText(Double.toString(dAvgRun2));
//Compare both scores to find the best score.
double dBest = dAvgRun1;
if (dAvgRun2 > dAvgRun1)
{
dBest = dAvgRun2;
}
//Sets text of lblBestScore to the highest of the two scores
jLabel_Best.setText(Double.toString(dBest));
似乎你的循环真的很小。在'dAvgRun1'的定义之后,我会在第一个循环的开头放置一个断点,然后调试应用程序。但要获得NaN,您可以将0.0除0.0。 –
关于代码质量的注意事项:您不仅可以构建双精度或整数数组。您还可以构建文本字段的数组(或更好的列表)。你知道,使用具有不同名称的12个文本字段来获取将存储在数组中的值是有点疯狂的。你正在重复代码12次,这可以通过使用一个文本字段数组来大大简化。 – GhostCat
@Jägermeister谢谢你的提示。我试图得到类似这样的东西来处理这个程序的前一个迭代,但我无法围绕它来包裹我的头。我一定会记得下次我需要做这样重复的事情。 – RThomP