我试图开发一个简单的应用程序,用于预测在给定某个年龄,班级,票价等的情况下乘客幸存泰坦尼克号的概率。我希望这些变量是动态的,并且希望使用底层脱字符模型计算预测的生存概率。插入符号和闪亮符号:无法创建由插入符号模式驱动的预测应用程序
当运行这段代码,我收到以下错误信息:
Warning: Error in [.data.frame: undefined columns selected Stack trace (innermost first): 70: [.data.frame 69: [ 68: sweep 67: predict.preProcess 66: predict 65: probFunction 64: predict.train 63: predict 62: predict 61: is.data.frame 60: data.matrix 59: observerFunc [#17] 4: 3: do.call 2: print.shiny.appobj 1: ERROR: [on_request_read] connection reset by peer
我的代码如下。任何想法是什么导致这个错误?非常感谢。
require(shiny)
require(plyr)
require(dplyr)
require(ggplot2)
require(caret)
require(xgboost)
require(titanic)
df=na.omit(titanic_train)
y=data.matrix(select(df, Survived))
y[y==0]="N"
y[y==1]="Y"
x=data.matrix(select(df, Pclass, Age, SibSp, Parch, Fare))
tCtrl <- trainControl(method = "repeatedcv", number = 3, repeats=3, summaryFunction = twoClassSummary, verbose=TRUE, classProbs = TRUE)
fit_xgbTree= train(x, y, method = "xgbTree" , family= "binomial", trControl = tCtrl, metric = "ROC", preProc = c("center", "scale"))
ui = pageWithSidebar(
headerPanel("Titanic"),
sidebarPanel(
radioButtons("Pclass", "Passenger Class", choices=c("1", "2", "3"),selected = "1", inline = TRUE,width = NULL),
sliderInput("Age", "Passenger Age", min=0, max=80, value=30),
radioButtons("SibSp", "SibSp", choices=c("0", "1", "2", "3", "4", "5")),
radioButtons("Parch", "Parch", choices=c("0", "1", "2", "3", "4", "5", "6")),
sliderInput("Fare", "Passenger Fare", min=0, max=520, value=35)
),
mainPanel(
dataTableOutput('testTable'),
textOutput('outputBox')
)
)
server=function(input, output){
values <- reactiveValues()
newEntry <- observe({ # use observe pattern
x=as.data.frame(matrix(0, nrow=1, ncol=5))
colnames(x)=c("Pclass", "Age", "SibSp", "Parch", "Fare")
x[1,1]=as.numeric(input$Pclass)
x[1,2]=input$Age
x[1,3]=as.numeric(input$SibSp)
x[1,4]=as.numeric(input$Parch)
x[1,5]=input$Fare
pred <- data.matrix(predict(object=fit_xgbTree, x, type="prob")[,2])
isolate(values$df <- x)
#isolate(values$df2 <- x)
})
output$testTable <- renderDataTable({values$df})
}
shinyApp(ui=ui, server=server)
我相信它可能有是由NA导致的...在'x [1,1] = as.numeric(输入$ Pclass)'中,由于输入$ PClass是选择“1st”,“2nd”,“3rd”,所以通过运行'as.numeric'来获得NAs。预测功能失败。所以你不会得到预测函数返回的矩阵,也不能运行'[,2]'。 – Jean
Pclass是数字。你可以通过运行唯一的(df $ Pclass) – user3725021
'input $ Pclass'来检查这个字符。 – Jean