孩子的扭转顺序

Question

我想使用模板来反转不同的XML序列; 例如：

<book title="Definitive XML Schema"> 
    <author first="Priscilla" /> 
    <chapter title="[I] "> 
    <section title="[I.1]" /> 
    <section title="[I.2]"> 
     <section title="[I.2.1]" /> 
     <section title="[I.2.2]" /> 
    </section> 
    <section title="[I.3] "> 
     <section title="[I.3.1]" /> 
    </section> 
    </chapter> 
    <chapter title="[II]"> 
    <section title="[II.1]" /> 
    <section title="[II.2]"> 
     <section title="[II.2.1]" /> 
     <section title="[II.2.2]" /> 
    </section> 
    </chapter> 
</book> 

我想要得到这样的输出：这是我的XSL。

<?xml version="1.0" encoding="UTF-8"?> 
<book title="Definitive XML Schema"> 
    <author first="Priscilla"/> 
    <chapter title="[I]"> 
     <section title="[I.3]"> 
     <section title="[I.3.1]"/> 
     </section> 
     <section title="[I.2]"> 
     <section title="[I.2.2]"/> 
     <section title="[I.2.1]"/> 
     </section> 
     <section title="[I.1]"/> 
    </chapter> 
    <chapter title="[II]"> 
     <section title="[II.2]"> 
     <section title="[II.2.2]"/> 
     <section title="[II.2.1]"/> 
     </section> 
     <section title="[II.1]"/> 
    </chapter> 
</book> 

是的，这些部分已被颠倒，但章节没有。

我尝试使用两个模板来解决它，但它不能工作..

<?xml version="1.0" encoding="UTF-8"?> 
<xsl:transform version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs"> 
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent ="yes"/> 
<xsl:template match="/"> 
<xsl:apply-templates/> 
<xsl:text>&#10;</xsl:text> 
</xsl:template> 

<xsl:template match="book"> 
    <xsl:copy> 
    <xsl:sequence select="@title"/> 
    <xsl:sequence select="author"/> 
    <xsl:apply-templates select="chapter"> 
    <xsl:with-param name="seq" select="section"/> 

    </xsl:apply-templates> 
    </xsl:copy> 
    </xsl:template> 

<xsl:template match ="chapter|section" as="element()"> 
    <xsl:param name="seq" as="element(section)*"/> 
    <xsl:copy> 
    <xsl:sequence select="@title"/> 
    <xsl:if test="not(empty($seq))"> 
    <xsl:apply-templates select="chapter"> 
     <xsl:with-param name="seq" select="$seq[position()>1]"/> 
    </xsl:apply-templates> 
    <xsl:apply-templates select="$seq[1]"/>  
    </xsl:if> 
    </xsl:copy> 
</xsl:template> 
</xsl:transform> 

Answer 1

这是一个更简单的XSLT 1.0（和2.0）解决方案：

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output omit-xml-declaration="yes" indent="yes"/> 
<xsl:strip-space elements="*"/> 

<xsl:template match="node()|@*"> 
    <xsl:copy> 
    <xsl:apply-templates select="node()|@*"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="*[section]"> 
    <xsl:copy> 
    <xsl:copy-of select="@*"/> 
    <xsl:apply-templates> 
    <xsl:sort select="position()" 
     data-type="number" order="descending"/> 
    </xsl:apply-templates> 
    </xsl:copy> 
</xsl:template> 
</xsl:stylesheet> 

当该变换被应用在下面的XML文档：产生

<book title="Definitive XML Schema"> 
    <author first="Priscilla" /> 
    <chapter title="[I] "> 
    <section title="[I.1]" /> 
    <section title="[I.2]"> 
     <section title="[I.2.1]" /> 
     <section title="[I.2.2]" /> 
    </section> 
    <section title="[I.3] "> 
     <section title="[I.3.1]" /> 
    </section> 
    </chapter> 
    <chapter title="[II]"> 
    <section title="[II.1]" /> 
    <section title="[II.2]"> 
     <section title="[II.2.1]" /> 
     <section title="[II.2.2]" /> 
    </section> 
    </chapter> 
</book> 

有用，正确的结果（翻转section元素的所有序列）：

<book title="Definitive XML Schema"> 
    <author first="Priscilla"/> 
    <chapter title="[I] "> 
     <section title="[I.3] "> 
     <section title="[I.3.1]"/> 
     </section> 
     <section title="[I.2]"> 
     <section title="[I.2.2]"/> 
     <section title="[I.2.1]"/> 
     </section> 
     <section title="[I.1]"/> 
    </chapter> 
    <chapter title="[II]"> 
     <section title="[II.2]"> 
     <section title="[II.2.2]"/> 
     <section title="[II.2.1]"/> 
     </section> 
     <section title="[II.1]"/> 
    </chapter> 
</book> 

Answer 2

这XSLT 2.0样式表：

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
    <xsl:strip-space elements="*"/> 
    <xsl:template match="node()|@*" name="identity"> 
     <xsl:copy> 
      <xsl:apply-templates select="node()|@*"/> 
     </xsl:copy> 
    </xsl:template> 
    <xsl:template match="chapter|section"> 
     <xsl:copy> 
      <xsl:apply-templates select="@*"/> 
      <xsl:apply-templates> 
       <xsl:sort select="tokenize(@title,'.')[last()]" 
          order="descending" 
          data-type="number"/> 
      </xsl:apply-templates> 
     </xsl:copy> 
    </xsl:template> 
</xsl:stylesheet> 

输出：

<book title="Definitive XML Schema"> 
    <author first="Priscilla"/> 
    <chapter title="[I] "> 
     <section title="[I.3] "> 
      <section title="[I.3.1]"/></section> 
     <section title="[I.2]"> 
      <section title="[I.2.2]"/> 
      <section title="[I.2.1]"/></section> 
     <section title="[I.1]"/> 
    </chapter> 
    <chapter title="[II]"> 
     <section title="[II.2]"> 
      <section title="[II.2.2]"/> 
      <section title="[II.2.1]"/></section> 
     <section title="[II.1]"/> 
    </chapter> 
</book>