ExpandableListView孩子顺序是过滤后的不正确

Question

嗨，这是我怎么添加的东西我expandablelist ..

listDataHeader = new ArrayList(Arrays.asList("Afghanistan", 
      "Albania", 
      "Algeria", 
      "Andorra", 
      "Angola", 
      "Anguilla", 
      "Antigua and Barbuda", 
      "Argentina", 
      "Armenia", 
      "Aruba",`........` 

listDataChild =新的HashMap>（）;

// Adding child data 
List<String> Afghanistan = new ArrayList<String>(); 
Afghanistan.add("Dari"); 
Afghanistan.add("Pashto"); 


List<String> Albania = new ArrayList<String>(); 
Albania.add("Albanian"); 
Albania.add("Greek"); 

List<String> Algeria = new ArrayList<String>(); 
Algeria.add("Arabic"); 
Algeria.add("French"); 
Algeria.add("Berber Dialects"); 

过滤

private class ItemFilter extends Filter { 
     @Override 
     protected FilterResults performFiltering(CharSequence constraint) { 

      String filterString = constraint.toString().toLowerCase(); 

      FilterResults results = new FilterResults(); 

      final List<String> list = originalData; 
      final HashMap<String, List<String>> childList = originalDatachild; 

      int count = list.size(); 
      final ArrayList<String> nlist = new ArrayList<String>(count); 
      final HashMap<String, List<String>> nlistChild= new HashMap<String, List<String>>(); 
      int counterFilter=0; 
      String filterableString ; 

      for (int i = 0; i < count; i++) { 
       filterableString = list.get(i); 
       if (filterableString.toLowerCase().contains(filterString)) { 
        nlist.add(filterableString); 
        /*int ii = i; 
        counterFilter++; 
        while(childList.get(ii)!=null) { 
         nlistChild.put(nlist.get(counterFilter),); 
         ii++; 


        }*/ 
       } 
      } 


      results.values = nlist; 

      results.count = nlist.size(); 

      return results; 
     } 

输出后是好的......但孩子的项目，不按父项。我不知道该怎么办。我想我必须找到一种替代的方式来增加孩子到列表中的以下现有方法..

listDataChild.put(listDataHeader.get(0), Afghanistan);//Header,Child data 
listDataChild.put(listDataHeader.get(1), Albania); 
listDataChild.put(listDataHeader.get(2), Algeria); 
listDataChild.put(listDataHeader.get(3), Andorra); 
listDataChild.put(listDataHeader.get(4), Angola); 
listDataChild.put(listDataHeader.get(5), Anguilla); 

任何帮助吗？

Answer 1

解决：

建立getChild（）和getChildrenCount（）妥善解决它。

public int getChildrenCount(int groupPosition) { 
    return this.filteredDatachild.get(this.filteredData.get(groupPosition)) 
      .size(); 
} 



public Object getChild(int groupPosition, int childPosititon) { 
     return this.filteredDatachild.get(this.filteredData.get(groupPosition)) 
       .get(childPosititon); 
    } 

和创建新的子名单如下：

for (int i = 0; i < count; i++) { 
      filterableString = list.get(i); 
      if (filterableString.toLowerCase().contains(filterString)) { 
       nlist.add(filterableString); 


       nchildlist.put(nlist.get(ii),originalDatachild.get(nlist.get(ii))); 
       ii++; 
       Log.d("Child Items:", "Child index:" + ii); 
      }