我有一个像下面多维数组发现两个日期
array(
"hgfh" => array("s" => "2011-11-28T07:00-04:00", "e" => "2011-11-29T06:59-04:00"),
"hgfh" => array("s" => "2011-11-29T07:00-04:00", "e" => "2011-11-30T06:59-04:00"),
"hgfh" => array("s" => "2011-11-30T07:00-04:00", "e" => "2011-12-01T06:59-04:00"),
"hgfh" => array("s" => "2011-12-01T07:00-04:00", "e" => "2011-12-02T06:59-04:00"),
"hgf" => array("s" => "2011-12-02T07:00-04:00", "e" => "2011-12-05T06:59-04:00"),
"sog" => array("s" => "2011-12-05T07:00-04:00", "e" => "2011-12-06T06:59-04:00"),
"gfd" => array("s" => "2011-12-06T07:00-04:00", "e" => "2011-12-07T06:59-04:00"),
"gfd" => array("s" => "2011-12-07T07:00-04:00", "e" => "2011-12-08T06:59-04:00"),
"bob" => array("s" => "2011-12-08T07:00-04:00", "e" => "2011-12-09T06:59-04:00"),
"tree" => array("s" => "2011-12-09T07:00-04:00", "e" => "2011-12-11T23:00-04:00"),
);
例如,一个数组中,我需要确定当前date("c");
是数组中的"s"
和"e"
之间再拿到键。所以它会说今天是2011-11-30T09:50-04:00
,并确定关键是hgfh
有没有快速和肮脏的方法来做到这一点?我对性能有点担心,所以如果有一种更好的性能方法,我会很感激。
你有相同的索引'hgfh' 4次,这是一个错误的复制和粘贴? –
这是垃圾数据哈哈 – Steven