2016-09-22 93 views
0

我刚开始使用Firebase编写新应用程序。问题在于缺少象以下错误的符号:auth_failed,minimum_password。我尝试重建项目,创建一个完整的新应用程序,但仍然失踪​​。Android无法解析符号auth_failed

我该如何解决这个问题?

public class MainActivity extends AppCompatActivity { 

private static final String TAG = "MainActivity"; 

private EditText etInputEmail; 
private EditText etInputPassword; 
private Button btnRegister; 

private FirebaseAuth mAuth; 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 

    etInputEmail = (EditText) findViewById(R.id.etInputEmail); 
    etInputPassword = (EditText) findViewById(R.id.etInputPassword); 
    btnRegister = (Button) findViewById(R.id.btnRegister); 

    mAuth = FirebaseAuth.getInstance(); 

    btnRegister.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View view) { 
      String email = etInputEmail.getText().toString().trim(); 
      String password = etInputPassword.getText().toString().trim(); 

      mAuth.createUserWithEmailAndPassword(email, password).addOnCompleteListener(this, new OnCompleteListener<AuthResult>() { 
       @Override 
       public void onComplete(@NonNull Task<AuthResult> task) { 
        Log.d(TAG, "createUserWithEmail:onComplete:" + task.isSuccessful()); 

        if (!task.isSuccessful()) { 
         Toast.makeText(MainActivity.this, R.string.auth_failed, Toast.LENGTH_SHORT).show(); 
        } 
       } 
      }); 
     } 
    }); 

} 
+0

只需在你的strings.xml文件中定义'auth_failed'字符串....如果你看样本代码中的strings.xml,你可以看到它定义在那里:https://github.com/firebase /quickstart-android/blob/master/auth/app/src/main/res/values/strings.xml –

+0

@DanielNugent谢谢。我的错误没有看代码! –

+0

要标记为已解决,请在下方添加答案,然后单击相邻的刻度图标。 – halfer

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