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我刚开始使用Firebase编写新应用程序。问题在于缺少象以下错误的符号:auth_failed,minimum_password。我尝试重建项目,创建一个完整的新应用程序,但仍然失踪。Android无法解析符号auth_failed
我该如何解决这个问题?
public class MainActivity extends AppCompatActivity {
private static final String TAG = "MainActivity";
private EditText etInputEmail;
private EditText etInputPassword;
private Button btnRegister;
private FirebaseAuth mAuth;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
etInputEmail = (EditText) findViewById(R.id.etInputEmail);
etInputPassword = (EditText) findViewById(R.id.etInputPassword);
btnRegister = (Button) findViewById(R.id.btnRegister);
mAuth = FirebaseAuth.getInstance();
btnRegister.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
String email = etInputEmail.getText().toString().trim();
String password = etInputPassword.getText().toString().trim();
mAuth.createUserWithEmailAndPassword(email, password).addOnCompleteListener(this, new OnCompleteListener<AuthResult>() {
@Override
public void onComplete(@NonNull Task<AuthResult> task) {
Log.d(TAG, "createUserWithEmail:onComplete:" + task.isSuccessful());
if (!task.isSuccessful()) {
Toast.makeText(MainActivity.this, R.string.auth_failed, Toast.LENGTH_SHORT).show();
}
}
});
}
});
}
只需在你的strings.xml文件中定义'auth_failed'字符串....如果你看样本代码中的strings.xml,你可以看到它定义在那里:https://github.com/firebase /quickstart-android/blob/master/auth/app/src/main/res/values/strings.xml –
@DanielNugent谢谢。我的错误没有看代码! –
要标记为已解决,请在下方添加答案,然后单击相邻的刻度图标。 – halfer