如何将每个文本文件行分隔为单独的列表？

Question

说我有一个包含以下内容的文本文件：

Bob 15 M 
John 16 M 
Jen 15 F 

我如何把它变成一个列表，该列表值：

listOne = ['Bob', '15', 'M'] 
listTwo = ['John', '16', 'M'] 
listThree = ['Jen', '15', 'F'] 

感谢

Answer 1

只是拆分它并将其解压缩

bob, john, jen = [a.split() for a in open(file)] 

Answer 2

用打开文件和分割（）：

with open('text.txt') as f: 
    strings = f.readlines() 
    data = [string.split() for string in strings] 

Answer 3

with open('text.txt') as file: 
    lines = file.readlines()  # Creates a list of lines 
    for line in lines: 
     line = line.split()   # Split each line into list of "words" 

这给你一个嵌套列表这可能是明智的。如果你迫切想3所列出，使用此：

evalvar = "" 
count = 0 
for line in lines: 
    count += 1 
    evalvar += "list"+str(count)+" = "+str(line)+";" 
exec(evalvar)           # Runs the evalvar which has 
                 # code in it. 

Answer 4

您可以在文件中适用string.split每一行：

import string 

with open('text.txt') as text: 
    result = map(string.split, text) 

使用Python 3，您需要兑现的map，否则文件没有按之前它关闭“吨得到阅读：

result = list(map(string.split, text)) 

然而，string.split已被废弃，只适用于str对象，正ot unicode。一个更普遍的解决方案是创建一个列表理解：

result = [line.split() for line in text]