我有一个数据帧test
的列是因素转换列字符与sapply
class(test)
[1] "data.frame"
sapply(test, class)
street city state
"factor" "factor" "factor"
如果我尝试将这些列转换为字符与sapply()
,不顺心的事,我不知道为什么
test <- as.data.frame(sapply(test, as.character))
sapply(test, class)
street city state
"factor" "factor" "factor"
我希望输出是所有字符列。为什么列不转换,以及如何将所有因子列转换为字符?
下面是测试数据:
> dput(test)
structure(list(street = structure(c(5L, 1L, 6L, 2L, 3L, 4L), .Label = c("12057 Wilshire Blvd",
"15300 Sunset Boulevard", "17380 Sunset Blvd", "1898 Westwood Blvd.",
"3006 Sepulveda Blvd.", "514 Palisades Drive"), class = "factor"),
city = structure(c(1L, 1L, 2L, 2L, 2L, 3L), .Label = c("Los Angeles",
"Pacific Palisades", "Westwood"), class = "factor"), state = structure(c(1L,
1L, 1L, 1L, 1L, 1L), .Label = "CA", class = "factor")), .Names = c("street",
"city", "state"), row.names = c(NA, -6L), class = "data.frame")
'sapply(data.frame(sapply(试验,as.character),stringsAsFactors = FALSE),类)' –
澄清@分贝的注释,当你运行'as.data.frame'时,它会携带一个默认参数'stringsAsFactors = TRUE',它将撤销你在'sapply'中做的工作。 – Benjamin