2017-01-10 40 views
0

我想在连接条件的列上爆炸。配置单元 - 在加入条件下爆炸

select 
t1.a,t2.b, t2.c 
from table1 AS t1 
join (select b,LATERAL VIEW explode(ABCD) AS c from person) AS t2 ON (t1.c=t2.c) 

但是,此查询失败。我怀疑子查询没有按预期工作。 在子查询中,我选择了两列,一列是列b,另一列是列c,这是一个爆炸。

这种编写子查询的方式是正确的吗?如果错了,我怎么能做到这一点。

错误:

Error while compiling statement: FAILED: SemanticException Cannot do equality join on different types: string and map<bigint,array<string>> 
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什么是你所得到的错误,你可以张贴日志? 你是否确定你的专栏名称是b表格? –

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@Rijulsahu:添加了错误信息 –

回答

2
CREATE TABLE people(b int,abcd array<String>); 

INSERT INTO people SELECT 1, ARRAY("bob", "alice", "tom") from dummy limit 1; 
INSERT INTO people SELECT 2, ARRAY("john", "mike", "jack") from dummy limit 1; 

create table table1(name string, salary int); 
insert into table1 values("bob",1000); 
insert into table1 values("alice",500); 

hive> select b,c from people LATERAL VIEW explode(ABCD) ep AS c; 
OK 
1  bob 
1  alice 
1  tom 
2  john 
2  mike 
2  jack 


hive> select 
t1.salary,t2.b, t2.c 
from table1 AS t1 
join (select b,c from people LATERAL VIEW explode(ABCD) ep AS c) AS t2 ON (t1.name=t2.c) 

OK 
1000 1  bob 
500  1  alice 
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编译语句时出错:FAILED:SemanticException不能对不同类型的字符串和地图进行平等连接:> –