PHP总状态列

Question

我有一个PHP脚本，我试图总结状态类型变量。例如，当我做到以下几点：

echo $val['status']; 

我得到：

新新新死在处理新新新新新死新死死新新新在工艺

我想要做的是总结所有这些状态类型，并将它们放入变量：

$statusnew 
$statusdead 
$statusinprocess 

所以如果我要做一个：

echo $statusnew; 

我会被提交与“12”等等等等。我对PHP非常陌生，所以我试图找出最有效的方法来做到这一点。我知道有一个array_sum函数，但不知道它会在这里工作，因为我们不是数字值的总和。

循环：

if($_SESSION['partner'] == 1) 
{ 


$query = "select l.id as lead_id , l.account_name as account_name , l.first_name as first_name , l.last_name as last_name,l.date_entered as date_entered , lc.endpoints_c as endpoints , l.status as status from leads as l 
        join leads_cstm as lc on lc.id_c = l.id       
        where lc.account_id_c = '".$_SESSION['account_id']."' 
        and l.deleted = '0' and l.status <> 'Converted' order by date_entered DESC"; 


$db -> PS_Pagination($query, 20, 5, ""); 
$db -> setDebug(true); 
$rs = $db->paginate(); 
$num_rows = mysql_num_rows($rs); 

脚本进一步下跌：

 while($val = mysql_fetch_assoc($rs)) 
     { 
      $date_create = date("m/d/Y", strtotime($val['date_entered'])); 

我刚刚从@Joseph添加什么：

 $count = array(); // for graph 

    // then, in your loop: 
    if (array_key_exists($val['status'], $count)) 
    $count[$val['status']]++; 
    else 
    $count[$val['status']] = 1; 

    echo $count['New']; 

Answer 1

$count = array(); 

while($val = mysql_fetch_assoc($rs)) 
{ 
    $date_create = date("m/d/Y", strtotime($val['date_entered'])); 

    if (array_key_exists($val['status'], $count)) 
     $count[$val['status']]++; 
    else 
     $count[$val['status']] = 1; 

    // continue with everything else being done in this loop 
} 

运行你的循环后，可以像这样访问计数：

$count['new']; // 12 
$count['dead']; // 4 
$count['in proccess']; // 2