php preg match只获取最后匹配的字符串

Question

我需要获取最后一个HTTP标头。我的字符串是：

HTTP/1.1 302 Moved Temporarily 
Date: Sat, 30 Apr 2016 09:48:56 GMT 
Server: Apache 
X-Powered-By: PHP/5.5.34 
Location: 2.php 
Content-Length: 0 
Content-Type: text/html 

HTTP/1.1 302 Moved Temporarily 
Date: Sat, 30 Apr 2016 09:48:57 GMT 
Server: Apache 
X-Powered-By: PHP/5.5.34 
Location: 3.php 
Content-Length: 0 
Content-Type: text/html 

HTTP/1.1 200 OK 
Date: Sat, 30 Apr 2016 09:48:57 GMT 
Server: Apache 
X-Powered-By: PHP/5.5.34 
Transfer-Encoding: chunked 
Content-Type: text/html 

但是我需要得到最后的标题。我试图用\ n \ n爆炸这个字符串，但我无法得到结果。 preg_match可以做到吗？

Answer 1

嘿！ 我需要与此代码爆炸它：

explode("\r\n\r\n", $header); 

Answer 2

使用preg_split和array_pop函数的溶液：

// $headers is your initial string 
$headers_splitted = preg_split("/\R{2}/", $headers); 

print_r(array_pop($headers_splitted)); 

输出：

HTTP/1.1 200 OK 
Date: Sat, 30 Apr 2016 09:48:57 GMT 
Server: Apache 
X-Powered-By: PHP/5.5.34 
Transfer-Encoding: chunked 
Content-Type: text/html