大厦黎平黄的问题,这似乎为我工作,以赶上今天还是最后一个工作日,所以类似的提法可能会为你做的问题更新:
worklogDate >= startOfDay(-1d) or (worklogDate >= startOfWeek(-2d) and worklogDate >= startOfDay(-3d))
(假设一个星期天为一周的开始和周一至周五工作天)
编辑:
worklogDate >= startOfDay(-1d) or (worklogDate <= startOfWeek(1d) and worklogDate >= startOfDay(-3d))
再次编辑:根据意见修正Bombproofing基于评论:
代表星期日周开始(北美,澳大利亚):
(worklogDate >= startOfDay(-1d) or (worklogDate >= startOfWeek(-2d) and worklogDate <= startOfWeek(1d) and worklogDate >= startOfDay(-3d))) and worklogDate < startOfDay()
对于本周星期一开始(欧洲):
(worklogDate >= startOfDay(-1d) OR worklogDate >= startOfWeek(-3d) AND worklogDate <= startOfWeek() AND worklogDate >= startOfDay(-3d)) AND worklogDate < startOfDay()
你尝试'startOfWeek()'方法? –
像'startOfWeek(-1)' –
我没有得到什么解决。你能否详细说明这个想法? –