我有以下代码,它将打开一个包含逗号分隔数字的文本文件。Python - 如何使用计数器逐行计数
from collections import Counter
with open("lottoresults.txt") as inf:
all_lines = [inf.read()]
print(all_lines)
for each_line in all_lines:
print(each_line)
counts = Counter(each_line)
set = each_line.replace("", "").split()
print(set)
for numbers in set:
nums = [int(i) for i in numbers.replace(",", "\n").split()]
print(nums)
for number in nums:
counts = Counter(nums)
print(counts)
的结果是:
['1,2,3,4,5\n1,3,5,6,7\n1,8,9,10,11']
1,2,3,4,5
1,3,5,6,7
1,8,9,10,11
['1,2,3,4,5', '1,3,5,6,7', '1,8,9,10,11']
[1, 2, 3, 4, 5]
[1, 3, 5, 6, 7]
[1, 8, 9, 10, 11]
Counter({8: 1, 1: 1, 10: 1, 11: 1, 9: 1})
我试图做到的是让程序读取的第一线,违背检查出现了许多的次数,然后读取第二行,重新计数(即将计数添加到以前的计数)。
我哪里错了?目前甚至没有计算数字,因为有超过1个“1”的实例。
提示:你是否观察到输出导致最后一个数组的计数?这意味着,计数器正在重新初始化,但没有更新。 –
我确实观察过它,但现在我明白了为什么它将数字计数为一次!谢谢。 –