如何在每个索引处包含多个值的nsmutablearray中的特定索引替换对象

Question

我的数组在每个索引处包含（firstName，lastName，age）。现在我想改变索引1处的年龄。请指导如何做到这一点。这是我的代码。

- (void)viewDidLoad { 
[super viewDidLoad]; 
productArray=[[NSMutableArray alloc]init]; 

PersonDetail *personObj = [[PersonDetail alloc] init]; 
personObj.firstName = @"Adeem"; 
personObj.lastName = @"Basraa"; 
personObj.age = @"5"; 

[productArray addObject:personObj]; 
[personObj release]; 

PersonDetail *personObj = [[PersonDetail alloc] init]; 
personObj.firstName = @"Ijaz"; 
personObj.lastName = @"Ahmed"; 
personObj.age = @"10"; 

[productArray addObject:personObj]; 
[personObj release]; 

PersonDetail *personObj = [[PersonDetail alloc] init]; 
personObj.firstName = @"Waqas"; 
personObj.lastName = @"Ahmad"; 
personObj.age = @"15"; 
[productArray addObject:personObj]; 
[personObj release]; 

}

Answer 1

Person *person = (Person *)[myArray objectAtIndex:1]; 
person.age = 2; 

假设Person是存储阵列中的自定义对象

Answer 2

假如你NSMutableArray由NSMutableDictionary对象，

尝试这样：

NSMutableDictionary* entry = [entries objectAtIndex:index]; 

[entry setValue:@"newAge" forKey:@"Age"]; 

Answer 3

使用本

[arrname replaceObjectAtIndex:1 withObject:[NSNumber numberWithInt:13]];//13 is the age you want to change 

Answer 4

试试这个

-insertObject:atIndex: or replaceObjectAtIndex:withObject: 

Answer 5

您应该使用NSMutableDictionary保存的姓名，年龄，电话，地址，并添加本字典到你的阵列。

[[arry objectAtIndex:1] setObject:@"value" forKey:@"key"]; 

像这样，你可以改变价值。

Answer 6

也许这会帮助你。

- (void)viewDidLoad { 
[super viewDidLoad]; 
productArray=[[NSMutableArray alloc]init]; 

PersonDetail *personObj = [[PersonDetail alloc] init]; 
personObj.firstName = @"Adeem"; 
personObj.lastName = @"Basraa"; 
personObj.phoneNumber = @"123456789"; 

[productArray addObject:personObj]; 
[personObj release]; 

PersonDetail *personObj = [[PersonDetail alloc] init]; 
personObj.firstName = @"Ijaz"; 
personObj.lastName = @"Ahmed"; 
personObj.phoneNumber = @"987654321"; 

[productArray addObject:personObj]; 
[personObj release]; 

PersonDetail *personObj = [[PersonDetail alloc] init]; 
personObj.firstName = @"Waqas"; 
personObj.lastName = @"Ahmad"; 
personObj.phoneNumber = @"45656789"; 
[productArray addObject:personObj]; 
[personObj release]; 
} 

- (void)change { 

for (int i=0;i<[productArray count];i++) { 
      PersonDetail *personObj = (PersonDetail *)[[productArray objectAtIndex:i] retain]; 
      personObj.phoneNumber = @"New"; 
    } 
}