工作where子句中没有与工作时,我写了其中Prse =“H”它显示了我一个错误“无效列”where子句中没有与
;with cT(FLDID ,FLD10 ,FLD610)
as
(
select * from Table556
inner join Table555 on table555.FLD9=FLD318
where FLD610=150
)
select case when fld609 <=12 then 'h' else 's' end as Prse,* from cT
where Prse ='h'
@Dems - 完成。好的结果(我通常不会在我的CTE中使用明确的列列表) –
thankx Damien_The_Unbeliever –