如何使子查询正确

嗨，大家好，我在SQL中有一些子查询的问题。我正在使用MS Access 2010并编写sql。如何使子查询正确

SELECT vak.Name, COUNT(vak.amount) AS [First], COUNT(vak2.amount2) AS [Second]  
FROM 
(SELECT kon.Name, (Count(icv.CV_ID)/Count(icv.CV_ID)) AS amount 
FROM (kon INNER JOIN v ON kon.K_ID = v.K_ID) INNER JOIN icv ON v.Vak_ID = icv.Vak_ID 
GROUP BY v.Vak_ID, kon.Name) AS vak, 
(SELECT kon.Name, COUNT(v.Vak_ID) AS amount2 
FROM (kon INNER JOIN v ON kon.K_ID = v.K_ID) INNER JOIN icv ON v.Vak_ID = icv.Vak_ID 
GROUP BY kon.Name) AS vak2 
GROUP BY vak.Konkursa_Nosaukums

当我在数据表视图中检查它们两列是相同的。 “First”中有6行，值分别为12,12,6,12,6,6。“Second”列中的值相同。当我将这段代码分成两部分并创建两个新的查询用于测试时，“First”列显示值2,2,1,2,1,1，第二个查询的值为3,3,1,2,1， 1。这两个列在分开时都有正确的值，但是当我将这些值合并时，一些未知的值就会显示为12（我不知道它将像12这样的数字放在哪里）。当我在最后一行之前放行
WHERE vak.amount = vak2.amount2时，它在两列中显示2,2,1,2,1,1。我想这只会从第一个子查询或东西。

如何使这些子查询正确，因此它们显示的值与它们分别写入时相同？

来源

2011-03-11 Rob

你能后，你已经采取了.... – 2011-03-11 22:42:28

样本数据和各个子查询具有apropriate组@ Nitin Midha在这里都是单独查询。第一个： SELECT vak.Name，COUNT（vak.skaits）as [Column Name] FROM （SELECT kon.Name，（Count（icv.CV_ID）/ Count（icv.CV_ID））AS amount FROM（ KON INNER JOIN v ON kon.Kon_ID = v.Kon_ID）INNER JOIN ICV ON v.Vak_ID = icv.Vak_ID GROUP BY v.Vak_ID，kon.Name）AS VAK GROUP BY vak.Name 二之一： SELECT kon.Name，COUNT（v.Vak_ID）AS amount2 FROM Kon INNER JOIN v ON kon.Kon_ID = v.Kon_ID GROUP BY Kon.Name 首先显示COUNT列中的2,2,1,2,1,1 ，第二个显示COUNT列中的3,3,1,2,1,1 – Rob 2011-03-11 23:32:23

我想你缺少一个连接条件，并在适当的组... ...检查我的答案，如果它是有意义的... – 2011-03-12 00:10:44

SELECT vak.Name, vak.amount AS [First], vak2.amount2 AS [Second] 
FROM 
(SELECT kon.Name, (Count(icv.CV_ID)/Count(icv.CV_ID)) AS amount 
FROM (kon INNER JOIN v ON kon.K_ID = v.K_ID) INNER JOIN icv ON v.Vak_ID = icv.Vak_ID 
GROUP BY v.Vak_ID, kon.Name) AS vak, 
(SELECT kon.Name, COUNT(v.Vak_ID) AS amount2 
FROM (kon INNER JOIN v ON kon.K_ID = v.K_ID) INNER JOIN icv ON v.Vak_ID = icv.Vak_ID 
GROUP BY kon.Name) AS vak2 
WHERE vak.Name = van2.Name

来源

2011-03-11 23:04:05 RichardTheKiwi

它显示错误，当我喜欢你，删除COUNT函数，并在最后添加WHERE。您绑定执行不包含指定表达式'First'的查询作为聚合函数的一部分。 – Rob 2011-03-11 23:43:37

我认为你缺少一个连接条件，并通过...

SELECT vak.Name, vak.amount AS [First], vak2.amount2 AS [Second] 
FROM 
(SELECT kon.Name, (Count(icv.CV_ID)/Count(icv.CV_ID)) AS amount 
FROM (kon INNER JOIN v ON kon.K_ID = v.K_ID) INNER JOIN icv ON v.Vak_ID = icv.Vak_ID 
GROUP BY v.Vak_ID, kon.Name) AS vak, 
(SELECT kon.Name, COUNT(v.Vak_ID) AS amount2 
FROM (kon INNER JOIN v ON kon.K_ID = v.K_ID) INNER JOIN icv ON v.Vak_ID = icv.Vak_ID 
GROUP BY kon.Name) AS vak2 
WHERE vak.Name = van2.Name

来源

2011-03-12 00:10:05

如何使子查询正确

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