不允许使用不适用

我是R新手，因此请原谅我，如果我错过了一些协议，但这里是我的问题：我正在创建临时向量以便在需要时添加'0'。我最终想要一个由12位数组成的值，如果情况并非如此，我将添加我需要的'0'值。但是，试图贴上我的临时指数与相应的零之后，我得到以下信息：不允许使用不适用

colnames(ALLMBRS) <- c("SSN","tracts","GeoBlock","GeoCodeBlck","GeoMatch") #TA Members Tracts 
#Remove special characters and decimals 
tmp1 <- str_replace_all(ALLMBRS$GeoCode,"[[:punct:]]","") 
#Temporary Vector of ALLMBRS 
tmp2 <- tmp1 
#Vectors of Indices used to add 0's 
add1 <- str_length(ALLMBRS$tracts) == 11 
add2 <- str_length(ALLMBRS$tracts) == 10 
add3 <- str_length(ALLMBRS$tracts) == 9 
add4 <- str_length(ALLMBRS$tracts) == 8 
add5 <- str_length(ALLMBRS$tracts) == 7 
#Paste temporary vector indices into temporary vector 
tmp2[add1] <- paste(tmp2[add1],"0",sep="") 
tmp2[add2] <- paste(tmp2[add2],"00",sep="") 
tmp2[add3] <- paste(tmp2[add3],"000",sep="") 
tmp2[add4] <- paste(tmp2[add4],"0000",sep="") 
tmp2[add5] <- paste(tmp2[add5],"00000",sep="")

数据示例：

[1] "0"   "0"   "0"   "0"   "0"   "0"   
[7] "0"   "360010146121" "720210310133" "0"   "517100023001" "90034808002" 
[13] "250158202021" "250158211004" "250138125003" "290470203002" "250138124031" "250158202033" 
[19] "250138019012" "250138112002"

我希望所有的值包含12位。所以，我想看到

[1]000000000000

和

[12]900348080020 

Error Message: Error in tmp2[add1] <- paste(tmp2[add1],"0",sep = ""): 
NAs are not allowed in subscripted assignments

如果我有NA在我的数据我怎么能绕过这个，所以我可以完成我的任务。谢谢你的帮助。

来源

2014-09-18 user3067851

您可以使用stringr中的str_pad填充字符串。在pad参数设置为"0"

> x <- c("0", "0", "0", "0", "0", "0", "0", "360010146121", 
     "720210310133", "0", "517100023001", "90034808002", 
     "250158202021", "250158211004", "250138125003", 
     "290470203002", "250138124031", "250158202033", 
     "250138019012", "250138112002") 
> library(stringr) 
> str_pad(x, 12, pad = "0") 
# [1] "000000000000" "000000000000" "000000000000" "000000000000" 
# [5] "000000000000" "000000000000" "000000000000" "360010146121" 
# [9] "720210310133" "000000000000" "517100023001" "090034808002" 
#[13] "250158202021" "250158211004" "250138125003" "290470203002" 
#[17] "250138124031" "250158202033" "250138019012" "250138112002"

更新：对于含有任何NA值向量，你可以做

x[!is.na(x)] <- str_pad(x[!is.na(x)], 12, pad = "0")

垫的价值观和离开的NA不变。例如，

> y <- c("0", NA, "123", "68") 
> y[!is.na(y)] <- str_pad(y[!is.na(y)], 12, pad = "0") 
> y 
# [1] "000000000000" NA    "000000000123" "000000000068"

来源

2014-09-18 22:43:00

谢谢理查德。我收到一条错误消息：'无效的时间值'。这是否会因为我将NA作为一些价值观？ – user3067851 2014-09-24 16:33:57

@ user3067851我刚试过，是的，它似乎是这样。试试'x [！is.na（x）] < - str_pad（x [！is.na（x）]，12，pad =“0”）;看看是否有效。如果这对您有用，我会更新答案。 – 2014-09-24 16:36:12

不允许使用不适用

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