两只骰子游戏的猪不能得分重置

Question

这里是我在网上找到的代码。我修改了它来滚动两个骰子，而不是一个，但是当蛇眼被滚动时我很难将分数重置为0。我已经尝试了一些东西，如重新分配我的原始值从顶部重置分数为0，但没有奏效。我只是处于亏损状态。

from random import randint 

playercount = 2 
maxscore = 100 
safescore = [0] * playercount 
player = 0 
score=0 

while max(safescore) < maxscore: 
    if player == 0: 
     rolling = 0 
     if score < 17 and score + safescore[player] < maxscore: 
      rolling = 1 
    else: 
     rolling = input("Player %i: (%i, %i) Rolling? (Y) " 
      % (player, safescore[player], score)).strip().lower() in {'yes', 'y', ''} 
    if rolling: 
     rolled = randint(1, 6) 
     rolled2 = randint(1, 6) 
     print(' Rolled %i' % rolled) 
     print(' Rolled %i' % rolled2) 
     if rolled ==1 and rolled2 ==1: 
       print(' Snake Eyes!! your score is set to 0') 

       score, player = 0, (player + 1) % playercount 
     elif rolled == 1: 
      print(' Bust! you lose %i but still keep your previous %i' 
        % (score, safescore[player])) 
      score, player = 0, (player + 1) % playercount 
     elif rolled2 == 1: 
      print(' Bust! you lose %i but still keep your previous %i' 
        % (score, safescore[player])) 
      score, player = 0, (player + 1) % playercount 


     else: 
      score += rolled + rolled2 
    else: 
     safescore[player] += score 
     if safescore[player] >= maxscore: 
      break 
     print(' Sticking with %i' % safescore[player]) 
     score, player = 0, (player + 1) % playercount 

print('\nPlayer %i wins with a score of %i' %(player, safescore[player])) 

Answer 1

嗯，我想通了，这是它需要如何修复。

if rolled ==1 and rolled2 ==1: 
       print(' Snake Eyes!! your score is set to 0') 
       safescore[player] = 0  
       player = (player + 1) % playercount