我是一个编码训练营一周,所以原谅我简单,可能草率编码,但我想知道如何能为我的两个球员骰子滚动游戏的胜利运行理货。如果球员想要继续比赛,我能够产生最后的比分并且循环回去重新开始,但是我想保持胜利的状态,以便球员知道每个球员赢了多少次。这里是我的功能:为骰子游戏运行的理论
def DiceRoll():
Dice1 = random.randint(1, 20)
Dice2 = random.randint(1, 12)
Dice3 = random.randint(1,6)
Dice4 = random.randint(1, 20)
Dice5 = random.randint(1, 12)
Dice6 = random.randint (1, 6)
DoubleDice1 = (((Dice1 + Dice2)*2) + Dice3)
DoubleDice2 = (((Dice1 + Dice3)*2) + Dice2)
DoubleDice3 = (((Dice2 + Dice3)*2) + Dice1)
DoubleDice4 = (((Dice4 + Dice5)*2) + Dice6)
DoubleDice5 = (((Dice4 + Dice6)*2) + Dice5)
DoubleDice6 = (((Dice5 + Dice6)*2) + Dice4)
TripleDice1 = ((Dice1 + Dice2 +Dice3) * 3)
TripleDice2 = ((Dice4 + Dice5 +Dice6) * 3)
print("Player 1, Roll?")
Roll = input("Y/N?")
if Roll =="y":
print("Ok!")
if Roll == "n":
print("Goodbye!")
time.sleep(2)
sys.exit(0)
print(" ")
print(Dice1, Dice2, Dice3)
Score1 = Dice1 + Dice2 + Dice3
if Dice1 == Dice2:
Score1 = DoubleDice1
print(Score1)
elif Dice1 ==Dice3:
Score1 = DoubleDice2
print(Score1)
elif Dice2 == Dice3:
Score1 = DoubleDice3
print(Score1)
elif Dice1 == Dice2 ==Dice3:
Score1 = TripleDice1
print(Score1)
else:
print(Dice1 + Dice2 + Dice3)
print("""
""")
print("Player 2, Roll?")
Roll2 = input("Y/N?")
if Roll2 =="y":
print("Ok!")
if Roll2 == "n":
print("Goodbye!")
time.sleep(2)
sys.exit(0)
print(" ")
print(Dice4, Dice5, Dice6)
Score2 = (Dice4 + Dice5 + Dice6)
if Dice4 == Dice5:
Score2 = DoubleDice4
print(Score2)
elif Dice4 == Dice6:
Score2 = DoubleDice5
print(Score2)
elif Dice5 == Dice6:
Score2 = DoubleDice6
print(Score2)
elif Dice4 == Dice5 ==Dice6:
Score2 = TripleDice2
print(Score2)
else:
print(Dice4 + Dice5 + Dice6)
print("""
""")
if Score1 > Score2:
print("Player 1:", Score1, "Player 2:", Score2)
print("Player 1 Wins!")
if Score1 < Score2:
print("Player 1:", Score1, "Player 2:", Score2)
print("Player 2 Wins!")
if Score1 == Score2:
print("Player 1:", Score1, "Player 2:", Score2)
print("Tie!")
这并不真正回答你的问题,但这里有一些代码清理的想法:'dice = [random.randint(1,20)for _in range(6)]'应该简化你的六个变量到一个 – inspectorG4dget
哪里你实际上调用'DiceRoll'? –