过滤SQL树查询

Question

如果我有一个如下所示的树查询，我想筛选Name ='Son'并选择所有的父记录，所以结果应该产生前3行。我将如何构建我的查询？我读过我应该使用公用表表达式（CTE），但我是CTE上的新手。谁能帮我？谢谢。

select 1 AS id, NULL AS parent, 'God' AS name 
    UNION 
    select 2 AS id, 1 AS parent, 'Father' AS name 
    UNION 
    select 3 AS id, 2 AS parent, 'Son' AS name 
    UNION 
    select 4 AS id, NULL AS parent, 'Godmother' AS name 
    UNION 
    select 5 AS id, 4 AS parent, 'Mother' AS name 

Answer 1

听起来像是你可以存储在一个表中的树（或使用上面的SQL定义视图），然后如果你使用的是Oracle，您可以使用CONNECT BY功能来筛选记录。

Answer 2

这是你在找什么？

;with SomeCTE as 
(
select * 
from (
select 1 AS id, NULL AS parent, 'God' AS name  
UNION  
select 2 AS id, 1 AS parent, 'Father' AS name  
UNION  
select 3 AS id, 2 AS parent, 'Son' AS name  
UNION  
select 4 AS id, NULL AS parent, 'Godmother' AS name  
UNION  
select 5 AS id, 4 AS parent, 'Mother' AS name) as a 
) 
select * 
from SomeCTE a 
left join SomeCTE b 
on a.parent = b.id 
left join SomeCTE c 
on b.parent = c.id 
where a.name = 'son'