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挣扎我是比较新的编码和一直负责创建C++中的井字游戏，我以为我把所有的代码完成，但也有各种问题，如用户输入没有被允许，只允许输入一个玩家的姓名而不是两个，任何帮助/建议你可以给我如何使这项工作将非常感激。与井字C++
#include <iostream>
using namespace std;
int menumain;
int oneplayer = 'X';
char square1('1');
char square2('2');
char square3('3');
char square4('4');
char square5('5');
char square6('6');
char square7('7');
char square8('8');
char square9('9');
void toggleplayers() {
if (oneplayer == 'X')
oneplayer = 'O';
else
oneplayer = 'X';
}
char win()
{
if (square1 == 'X' && square2 == 'X' && square3 == 'X') return 'X';
if (square4 == 'X' && square5 == 'X' && square6 == 'X') return 'X';
if (square7 == 'X' && square8 == 'X' && square9 == 'X') return 'X';
if (square1 == 'X' && square5 == 'X' && square9 == 'X') return 'X';
if (square3 == 'X' && square5 == 'X' && square7 == 'X') return 'X';
if (square3 == 'X' && square6 == 'X' && square9 == 'X') return 'X';
if (square1 == 'X' && square4 == 'X' && square7 == 'X') return 'X';
if (square2 == 'X' && square5 == 'X' && square8 == 'X') return 'X';
if (square1 == 'O' && square2 == 'O' && square3 == 'O') return 'O';
if (square4 == 'O' && square5 == 'O' && square6 == 'O') return 'O';
if (square7 == 'X' && square8 == 'X' && square9 == 'X') return 'X';
if (square1 == 'O' && square5 == 'O' && square9 == 'O') return 'O';
if (square3 == 'O' && square5 == 'O' && square7 == 'O') return 'O';
if (square3 == 'O' && square6 == 'O' && square9 == 'O') return 'O';
if (square1 == 'O' && square4 == 'O' && square7 == 'O') return 'O';
if (square2 == 'O' && square5 == 'O' && square8 == 'O') return 'O';
return '/';
}
int main() {
int playerone, playertwo;
system("cls");
cout << "tic tac toe" << endl;
cout << "-----------" << endl;
cout << "Start game (1)" << endl;
cout << "Quit game (2)" << endl;
cout << "Press 1 or 2 to proceed." << endl;
cin >> menumain;
if (menumain == 2)
{
return 0;
} else {
cout << "Player One, please enter your name: " << endl;
cin >> playerone;
system("cls");
cout << "Player Two, please enter your name: " << endl;
cin >> playertwo;
system("cls");
int playermove;
cout << "Choose a number between 1-9 to place!" << endl;
cin >> playermove;
if (playermove == 1)
square1 = oneplayer;
else if (playermove == 2)
square2 = oneplayer;
else if (playermove == 3)
square3 = oneplayer;
else if (playermove == 4)
square4 = oneplayer;
else if (playermove == 5)
square5 = oneplayer;
else if (playermove == 6)
square6 = oneplayer;
else if (playermove == 7)
square7 = oneplayer;
else if (playermove == 8)
square8 = oneplayer;
else if (playermove == 9)
square9 = oneplayer;
cout << "Tic tac toe!" << endl;
cout << "------------" << endl;
cout << " " << square1 << " | " << square2 << " | " << square3 << " "
<< endl;
cout << " " << square4 << " | " << square5 << " | " << square6 << " "
<< endl;
cout << " " << square7 << " | " << square8 << " | " << square9 << " "
<< endl;
cout << " " << endl;
cout << playerone << endl;
cout << playertwo << endl;
while (1) {
if (win() == 'X') {
cout << playerone << " wins!" << endl;
break;
}
else if (win() == 'O') {
cout << playertwo << " wins!" << endl;
break;
}
toggleplayers();
}
system("pause");
return 0;
}
}
** '用户输入没有被允许' **？无论您是否允许，您都可以使用它 –
您可以通过在板上使用2维数组来简化和缩短代码。 –
你写过你的代码的方式，你很幸运，tic-tac-toe只是一个3 x 3的板子。如果您的代码是10 x 10，您的代码会是什么样子？确定代码中的模式，看看是否有一种方法可以推广 - 二维矩阵的建议只是缩短代码的一个步骤。 – PaulMcKenzie