SQL - 查找具有相同值的不同名称

Question

例如，

在“汽车”表中，您有'法拉利'出现4次。而'兰博基尼'和'福特'出现4次。

您如何通过SQL指令显示'Car'中与法拉利具有相同价值/数量的所有车辆？

任何帮助表示赞赏。

感谢

Answer 1

select brand from car 
group by brand 
having count(*) = (select count(*) from car where brand = 'Ferrari') 

行，太慢了...这是为老板正在添加:-)

Answer 2

SELECT COUNT(make) FROM Car WHERE make = 'Ferrari' 

Answer 3

SELECT 
    Name 
FROM 
    Cars 
GROUP BY 
    Name 
HAVING 
    Count(Name) = (
    SELECT 
     Count(*) 
    FROM 
     Cars 
    WHERE 
     Name = "Ferrari" 
    ) 

Answer 4

这个怎么样

with a as 
(
select make, count(*) tot from car 
group by make 
) 
select * from a where a.tot = (select tot from a where make='Ferrari');