如何从订单日期获取当前日期以获得预期日期老化数

Question

更新： 我想通了，对于之前缺乏细节感到抱歉。我必须将日期转换为2017年12月4日显示，而不是原来的20170412，然后每天分解。

SELECT 
    PHPICK00.PHORDT "Days Aging", 
    COUNT(DISTINCT(PHPICK00.PHPKTN)) "Total Orders" 
    FROM 
    PHPICK00 
    WHERE 
    PHPICK00.PHORDT>= 0 
    GROUP BY 
    PHPICK00.PHORDT SELECT COUNT(PHPCTL) "Orders",         
    CASE When              
    SUBSTR(DIGITS(PHSTDT),6,2)||'/'||              
    SUBSTR(DIGITS(PHSTDT),8,2)||'/'||              
    SUBSTR(DIGITS(PHSTDT),2,4) = current date -1 days then '1 Day' 
    when               
    SUBSTR(DIGITS(PHSTDT),6,2)||'/'||              
    SUBSTR(DIGITS(PHSTDT),8,2)||'/'||              
    SUBSTR(DIGITS(PHSTDT),2,4) = current date -2 days then '2 Day' 
    when               
    SUBSTR(DIGITS(PHSTDT),6,2)||'/'||              
    SUBSTR(DIGITS(PHSTDT),8,2)||'/'||                
    SUBSTR(DIGITS(PHSTDT),2,4) = current date -3 days then '3 Day'  
    when                 
    SUBSTR(DIGITS(PHSTDT),6,2)||'/'||                
    SUBSTR(DIGITS(PHSTDT),8,2)||'/'||                
    SUBSTR(DIGITS(PHSTDT),2,4) = current date -3 days then '4+ Days' 
    else 'Ship Start Date Not Yet Met' END AS "Days Aging"          

    FROM PHPICK00              
    WHERE PHPSTF < '90' AND PHSTDT > 0 

---

我想有return语句显示天数顺序老化。所有我能够检索的日期为通用格式“20170412”，而我希望它输出“1”，“2”，“3”等。

我对SQL很陌生！希望这是一个简单的解决方案。

SELECT 
    PHPICK00.PHORDT "Order Date", 
    COUNT(DISTINCT(PHPICK00.PHPKTN)) "Total Orders" 
FROM PHPICK00 
WHERE PHPICK00.PHORDT = PHPICK00.PHORDT - GETDATE() 
GROUP BY PHPICK00.PHORDT 
ORDER BY PHPICK00.PHORDT DESC 

Answer 1

我想你想要这个 - 有点难以告诉寿。可能希望在你的问题中更清楚。

DATEDIFF(day,PHPICK00.PHORDT,GETDATE())