我得到一个错误,说“mysqli_fetch_array()期望参数1为mysqli_result,null给出”但一切看起来不错。我在想什么或在这里添加?它说错误在第41行。我感谢你看着这个 - 这让我疯狂!mysqli_fetch_array()期望参数1是mysqli_result,null给出
<html>
<head>
<title>Search</title>
</head>
<body>
<h1>Search</h1>
<form method="post" action="search.php">
<input type="hidden" name="submitted" value="true" />
<label> Search | Category:
<select name="category">
<option value="name">Name</option>
<option value="date">Date</option>
</select>
</label>
<label>Search Criteria: <input type="text" name="criteria" /></label>
<input type="submit" />
</form>
<?php
if (isset($_POST['submitted'])) {
// connect to DB
include('connect.php');
$category = $_POST['category'];
$criteria = $_POST['criteria'];
$query = "SELECT * FROM calls WHERE $category = '$category'";
$result = mysqli_query ($dbcon, $query) or die ('Error');
echo "<table>";
echo "<tr> <th>Date</th> <th>Name</th>";
}
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
echo "<tr><td>";
echo $row ['date'];
echo "<tr><td>";
echo $row ['name'];
}
?>
</body>
</html>
我把它调低了,但我得到一个错误,说“意外}” - 任何想法?你能发布你提出的确切更改吗? –