SQL服务器：在SQL查询计算序列

Question

我有以下四个表中的SQL Server 2008 R2：

DECLARE @ParentGroup TABLE (ParentGroup_ID INT, ParentGroup_Name VARCHAR(100)); 
DECLARE @ChildGroup TABLE (ChildGroup_id INT, ChildGroup_name VARCHAR(100), ParentGroup_id INT); 
DECLARE @Entity TABLE ([Entity_id] INT, [Entity_name] VARCHAR(100)); 
DECLARE @ChildGroupEntity TABLE (ChildGroupEntity_id INT, ChildGroup_id INT, [Entity_ID] INT); 
INSERT INTO @parentGroup VALUES (1, 'England'), (2, 'USA'); 
INSERT INTO @ChildGroup VALUES (10, 'Sussex', 1), (11, 'Essex', 1), (12, 'Middlesex', 1); 
INSERT INTO @entity VALUES (100, 'Entity0'),(101, 'Entity1'),(102, 'Entity2'),(103, 'Entity3'),(104, 'Entity4'),(105, 'Entity5'),(106, 'Entity6'); 
INSERT INTO @ChildGroupEntity VALUES (1000, 10, 100), (1001, 10, 101), (1002, 10, 102), (1003, 11, 103), (1004, 11, 104), (1005, 12, 100), (1006, 12, 105), (1007, 12, 106); 
/* 
SELECT * FROM @parentGroup 
SELECT * FROM @ChildGroup 
SELECT * FROm @entity 
SELECT * FROM @ChildGroupEntity 
*/ 

，如下表之间的关系：

SELECT ParentGroup_Name, ChildGroup_name, [Entity_name], 0 [ChildGroupSequence], 0 [EntitySequence] 
FROM @ChildGroupEntity cge 
INNER JOIN @ChildGroup cg ON cg.ChildGroup_id=cge.ChildGroup_id 
INNER JOIN @parentGroup pg ON pg.parentGroup_id=cg.parentGroup_id 
INNER JOIN @entity e ON e.[entity_id]=cge.[Entity_ID] 
ORDER BY ParentGroup_Name, ChildGroup_name, [Entity_name] 

上述输出查询是：

------------------------------------------------------------------------------- 
ParentGroup_Name|ChildGroup_name|Entity_name|ChildGroupSequence|EntitySequence| 
------------------------------------------------------------------------------- 
England   |Essex   |Entity3 |0     |0    | 
England   |Essex   |Entity4 |0     |0    | 
England   |Middlesex  |Entity0 |0     |0    | 
England   |Middlesex  |Entity5 |0     |0    | 
England   |Middlesex  |Entity6 |0     |0    | 
England   |Sussex   |Entity0 |0     |0    | 
England   |Sussex   |Entity1 |0     |0    | 
England   |Sussex   |Entity2 |0     |0    | 
------------------------------------------------------------------------------- 

现在，我想找出与子组相关的子组和所有实体对于父组1。此外，我要计算的[ChildGroupSequence]，[EntitySequence]作为用于以下的逻辑：

1. 的ChildGroupSequence列应父组内表示子组的序列，从1000开始并递增通过100.即第一个子组将为1000，第二个子组将为1100.
2. EntitySequence列应表示子组内的实体序列，从100开始并递增单个数字，为​​每个子组重新设置。即在100 childgroup 1点开始的第一个实体，如childgroup做的第一实体2

因此，输出应该采用以下格式：

------------------------------------------------------------------------------- 
ParentGroup_Name|ChildGroup_name|Entity_name|ChildGroupSequence|EntitySequence| 
------------------------------------------------------------------------------- 
England   |Essex   |Entity3 |1000    |100   | 
England   |Essex   |Entity4 |1000    |101   | 
England   |Middlesex  |Entity0 |1100    |100   | 
England   |Middlesex  |Entity5 |1100    |101   | 
England   |Middlesex  |Entity6 |1100    |102   | 
England   |Sussex   |Entity0 |1200    |100   | 
England   |Sussex   |Entity1 |1200    |101   | 
England   |Sussex   |Entity2 |1200    |102   | 
------------------------------------------------------------------------------- 

我可以很容易地阅读做到这一点值添加到应用程序层（.Net程序）中，但想通过尝试一些这样的小东西来学习SQL服务器。任何人都可以帮我写这个SQL查询吗？

任何帮助将不胜感激。提前致谢。

编辑： 我的示例数据似乎没有正确反映第一条规则，该规则指出ChildGroupSequence应该增加100，并且示例输出增加1.第二个查询反映增量100。@jpw ：非常感谢你指出这一点。

Answer 1

我相信这可以通过使用像这样partitioning和ranking功能来完成：

SELECT ParentGroup_Name, ChildGroup_name, [Entity_name], 
    999 + DENSE_RANK() OVER(PARTITION BY ParentGroup_Name ORDER BY ChildGroup_name) AS [ChildGroupSequence], 
    99 + ROW_NUMBER() OVER(PARTITION BY ParentGroup_Name, ChildGroup_name ORDER BY ChildGroup_name, Entity_name) AS [EntitySequence] 
FROM @ChildGroupEntity cge 
INNER JOIN @ChildGroup cg ON cg.ChildGroup_id=cge.ChildGroup_id 
INNER JOIN @parentGroup pg ON pg.parentGroup_id=cg.parentGroup_id 
INNER JOIN @entity e ON e.[entity_id]=cge.[Entity_ID] 
ORDER BY ParentGroup_Name, ChildGroup_name, [Entity_name] 

此查询会生成您所描述的样本输出。您的样本数据似乎并没有正确地反映第一条规则，虽然作为规则规定，ChildGroupSequence应该由100递增和1采样输出增加第二个查询反映100增量：

SELECT ParentGroup_Name, ChildGroup_name, [Entity_name], 
    900 + 100 * DENSE_RANK() OVER(PARTITION BY ParentGroup_Name ORDER BY ChildGroup_name) AS [ChildGroupSequence], 
    99 + ROW_NUMBER() OVER(PARTITION BY ParentGroup_Name, ChildGroup_name ORDER BY ChildGroup_name, Entity_name) AS [EntitySequence] 
FROM @ChildGroupEntity cge 
INNER JOIN @ChildGroup cg ON cg.ChildGroup_id=cge.ChildGroup_id 
INNER JOIN @parentGroup pg ON pg.parentGroup_id=cg.parentGroup_id 
INNER JOIN @entity e ON e.[entity_id]=cge.[Entity_ID] 
ORDER BY ParentGroup_Name, ChildGroup_name, [Entity_name] 

请参阅这两个查询的例子这个sample SQL Fiddle。

也许查询应通过ID分区，而不是名字，如果是这样苏塞克斯将埃塞克斯来之前，因为它具有较低的ID和查询是这样的：

SELECT ParentGroup_Name, ChildGroup_name, [Entity_name], 
    900 + 100 * DENSE_RANK() OVER(PARTITION BY pg.ParentGroup_ID ORDER BY cg.ChildGroup_ID) AS [ChildGroupSequence], 
    99 + ROW_NUMBER() OVER(PARTITION BY pg.ParentGroup_ID, cg.ChildGroup_ID ORDER BY cg.ChildGroup_ID, cge.Entity_ID) AS [EntitySequence] 
FROM @ChildGroupEntity cge 
INNER JOIN @ChildGroup cg ON cg.ChildGroup_id=cge.ChildGroup_id 
INNER JOIN @parentGroup pg ON pg.parentGroup_id=cg.parentGroup_id 
INNER JOIN @entity e ON e.[entity_id]=cge.[Entity_ID] 
ORDER BY pg.ParentGroup_ID, cg.ChildGroup_ID, [Entity_name] 

Answer 2

SELECT ParentGroup_Name, 
     ChildGroup_name, 
     [Entity_name], 
     LU.R [ChildGroupSequence], 
     99 + ROW_NUMBER() OVER (PARTITION BY LU.ParentGroup_id,LU.ChildGroup_id ORDER BY ChildGroup_name) [EntitySequence] 
FROM @ChildGroupEntity cge 
JOIN (
     SELECT cg.ChildGroup_id, 
       cg.ChildGroup_name, 
       pg.ParentGroup_id, 
       pg.ParentGroup_Name,  
       999 + (ROW_NUMBER() OVER (ORDER BY cg.ChildGroup_id)) [R] 
     FROM @ChildGroup cg 
     JOIN @parentGroup pg On pg.ParentGroup_ID = cg.ParentGroup_ID) LU 
     ON  cge.ChildGroup_id = LU.ChildGroup_id 
INNER JOIN @entity e ON e.[entity_id]=cge.[Entity_ID] 
ORDER BY LU.ParentGroup_Name, LU.ChildGroup_name, e.[Entity_name] 

结果：

Answer 3

您可以通过使用ranking functions

012解决这个

结果你可以在这里找到SQL Fiddle