如何显示给定人的所有行的总和

Question

我正在尝试编写一个SQL查询来显示每个用户的某些值的输入量。

下面是我在MySQL中使用的表格。这些表不包含任何FK，仅包含用于性能目的的PK。

表LIST_DETAILS：

表USERS：

表配置：

下面是我尝试过的SQL查询。我遇到的问题是它只显示一个用户，而不是我期望的250个用户。

select job_name, concat(fname,' ',lname), 
     sum(disposition_category = 'Attempts') as Attempts, 
     sum(disposition_category = 'RPC') as RPC, 
     sum(disposition_category = 'Contacts') as Contacts, 
     sum(disposition_category = 'Voted') as Voted, 
     sum(disposition_category = 'RPC and Voted') as 'RPC and Voted', 
     sum(disposition_category = 'Other') as Other, 
     sum(disposition_category = 'Directory Assistance') as 'Directory Assistance' 
from list_details ld 
    join users u ON u.id = ld.id 
    join dispositions d ON d.id = u.id 
where security_level = 1; 

这是我想看到的输出，但它只显示一个用户，当我需要看到250显示。

|  job_name   | concat(fname,' ',lname) | Attempts | RPC | Contacts | Voted | RPC and Voted | Other | Directory Assistance | 
| SPDR-lower-range8-8-14 |  Rosybel Abreu  | 11 | 10 | 7  | 0 |  0  | 9 |   1   | 

任何人都可以帮助我纠正我的错误吗？

Answer 1

您在这里遇到的问题是因为SUM()是一个聚合函数，它是对整个组进行求和的函数。

您正在将整个员工组合成一行。您需要添加GROUP BY子句，以便MySQL知道将哪些组进行求和的值。在这种情况下，我想你想按用户ID分组，所以试试这个：

SELECT job_name, CONCAT(fname,' ',lname) AS name, 
    SUM(disposition_category = 'Attempts') as Attempts, 
    SUM(disposition_category = 'RPC') AS RPC, 
    SUM(disposition_category = 'Contacts') AS Contacts, 
    SUM(disposition_category = 'Voted') AS Voted, 
    SUM(disposition_category = 'RPC and Voted') AS 'RPC and Voted', 
    SUM(disposition_category = 'Other') AS Other, 
    SUM(disposition_category = 'Directory Assistance') AS 'Directory Assistance' 
FROM list_details ld 
JOIN users u ON u.id = ld.id 
JOIN dispositions d ON d.id = u.id 
WHERE security_level = 1 
GROUP BY u.id;