Python随机卡片经销商 - 面卡计数器不能正确计数

Question

我正在练习编写这个课程。我必须处理扑克牌，直到发出四张A牌为止，最后，我还必须计算处理了多少张面牌（插孔，皇后，国王牌）。我没有为卡名写字典，因为我的老师特意告诉我们做随机整数命令。然而，除了脸部计数器（f_counter）之外，一切都可以工作。出于某种原因，它总是少计一张面卡。有谁知道为什么？谢谢！

print("You were dealt:\n") 

import random 

# This is the initial counter for the number of cards dealt. 
t_counter = 0 

# This is the initial counter for the number of aces dealt. 
a_counter = 0 

# This is the initial counter for the number of face cards dealt. 
f_counter = 0 

# This is so both a rank and a suit are dealt. 
r = random.randint(1,13) 
s = random.randint(1,4) 

while a_counter < 4: 

    # This counts and tells the user of each card dealt that isn't an ace. 
    r = random.randint(1,13) 
    s = random.randint(1,4) 
    t_counter += 1 

    if r == 11: 
     rank = "Jack" 
    elif r == 12: 
     rank = "Queen" 
    elif r == 13: 
     rank = "King" 
    elif r > 1: 
     rank = r 

    if s == 1: 
     suit = "Spades" 
    elif s == 2: 
     suit = "Hearts" 
    elif s == 3: 
     suit = "Diamonds" 
    elif s == 4: 
     suit = "Clubs" 
    print("Card",t_counter,': A',rank,"of",suit,) 

    # This counts the aces. 
    if r == 1: 
     a_counter += 1 
     print("An Ace of",suit,"!") 

    # This counts the face cards. 
    if r == 11 or r == 12 or r == 13: 
     f_counter += 1 

    # This allows up to four aces and also prints the number of face cards as the last thing. 
    if a_counter == 4: 
     print("You got",f_counter,"face cards!") 
     break 

Answer 1

我想我找到了它。考虑一下你有面子牌的情况。

设r = 11

排名 - > '杰克'

套装 - >什么

打印（ '无论杰克'）

增量f_counter

//下一次迭代

我们通过如果秩秩因为不是11,12,13或> 1，因此排名语句=“杰克”

打印（“其他一些诉讼插孔R = 1

秋季）

增量a_counter（因为轧制R = 1）

秋季通过的可能性f_counter

递增因此，您已印刷的面卡不增加f_counter。

Answer 2

我对你的程序做了一些修改。让我知道这是否能给出你想要的结果，并且我可以解释主要的变化。

rank = '' 

while a_counter < 4: 

    # This counts and tells the user of each card dealt that isn't an ace. 
    r = random.randint(1,13) 
    s = random.randint(1,4) 
    t_counter += 1 


    if s == 1: 
     suit = "Spades" 
    elif s == 2: 
     suit = "Hearts" 
    elif s == 3: 
     suit = "Diamonds" 
    elif s == 4: 
     suit = "Clubs" 

    if r == 11: 
     rank = "Jack" 
     f_counter += 1 
    elif r == 12: 
     rank = "Queen" 
     f_counter += 1 
    elif r == 13: 
     rank = "King" 
     f_counter += 1 
    elif r > 1 and r < 11: 
     rank = r 
    elif r == 1: 
     rank == "Ace" 
     a_counter += 1 

    if r == 1: 
     print("Card %d: An Ace of %s! **") % (t_counter, suit) 
    else: 
     print("Card %d: a %s of %s") % (t_counter, rank, suit) 

    if a_counter == 4: 
     print("You got %d face cards!") % (f_counter) 
     break 

这似乎是为我工作，但没有什么在你的程序将防止同一张卡调高两次（或更多）...