如何使用JQuery和Laravel从数据库中删除

Question

如果用户保存了文章，我使用if语句获得以下代码。我只是试图用jquery从数据库中删除文章。我不确定哪里会出错？非常感谢帮助！

查看：

<form action="{{URL::route('article-delete')}}" method="post" id="article_one_delete"> 
<div class="form-group"> 
<input type="hidden" name="first_desc" value="{{$firstrow->description}}" class="form-control"> 
</div> 
<div class="form-group"> 
<input type="hidden" name="first_title" value="{{$firstrow->title1}}" class="form-control"> 
</div> 

<button type ="button" id="Recodelete" class="btn btn-success btn-xs">UnSave</button> 
{{Form::token()}} 

</form> 

路线：

Route::delete('/home/', array('as' => 'article-delete', 
'uses' => 'HomeController@deletearticle')); 

控制器：

public function deletearticle(){ 

$firsttitle  = Input::get('first_title'); 

$articledelete = UserSaveArticle::where('user_id', Auth::id() 
->where ('user_save_articles.chosen_title', $firsttitle))->delete(); 

return true; 

JQuery的：

$(document).ready(function(){ 
    $('#Recodelete').on('click', function(){ 
     var article_one_delete = $('#article_one_delete').serializeArray(); 
     var url_d   = $('#article_one_delete').attr('action'); 

     $.get(url_d, article_one_delete, function(data){ 
      console.log(data); 
     }); 
    }); 
}); 

Answer 1

1. 应该定义右路线DELETE制品，这样的：

Route::delete('/article/{id}', ['as' => 'article-delete', 'uses' => 'HomeController@deleteArticle']); 

在HomeController $ id变量（物品ID）将可作为方法的参数：

function deleteArticle($id) 
{ 
    … 
} 

在PHP侧你定义DELETE路线，这意味着你应该使用ajax上JS侧DELETE请求方法：

$.ajax({ 
    url: '/article/' + articleId, 
    type: 'DELETE', 
    success: function(result) { 
     // Do something with the result 
    } 
});