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我正在尝试创建一个Rochambeau游戏。我困在查询lastThrow。这个查询将从计算机和播放器中引发并输出“Computer throws :: Rock,Paper或Scissors ::”最后一部分应该引用makeThrow查询。无论玩家/电脑是否抛出,我的lastThrow方法总是将“Rock”放在一边。对于如何解决这个问题,有任何的建议吗?Rochambeaua游戏(字符串输出)
import java.lang.Object;
import java.util.Random;
public class RochambeauPlayer{
public int wins;
public String name;
public int lastThrow;
public int throwMade;
public RochambeauPlayer(java.lang.String name){
this.name = name;
}
public java.lang.String getName(){
return name;
}
public int getWins(){
return wins;
}
public void incrementWins(){
wins++;
}
public int makeThrow(){
Random rand = new Random();
int throwMade = rand.nextInt(3);
Rochambeau.rock = 0;
Rochambeau.paper = 1;
Rochambeau.scissors = 2;
return throwMade;
}
public int makeThrow(int throwType){
// RETURNS RANDOM (SO COMPUTER DOESNT ALWAYS WIN)
Random rand = new Random();
int throwMade = rand.nextInt(3);
if (throwType == Rochambeau.rock){
return throwMade;
} else if (throwType == Rochambeau.paper){
return throwMade;
} else if (throwType == Rochambeau.scissors){
return throwMade;
} else {
return throwMade;
}
}
public java.lang.String lastThrow(){
if (throwMade == 0){
return "Rock";
} else if (throwMade == 1){
return "Paper";
} else if (throwMade == 2){
return "Scissors";
} else {
return "No Throw";
}
}
public java.lang.String toString(){
return name + " has " + wins + " win(s).";
}
}
如果我这样做,我怎样才能将我的lastThrow方法中的throwMade更改为? –
请参阅更新的安装程序。方法中只分配值不再声明变量。 – iMBMT
我做到了,但现在我得到一个错误,说throwMade不是一个变量,无法找到。 –