我想将64位纯文本转换为二进制文件。您可以在下面的代码中看到我已将plain_Text64
和binary_Plain_Text64
分配为全局变量。但在执行函数hexToBin
后,binary_Plain_Text64
的值应该是给定64位纯文本的新二进制值。不幸的是我得到了其他一些。我已经在hexToBin
函数本身中打印了binary_Plain_Text64
的值,它的工作原理非常完美。谁能帮我?在C显示错误的输出十六进制到二进制转换
#include<stdio.h>
#include<string.h>
int * hexToBin(char plain_Text64[]);
char plain_Text64[17]={};
int binary_Plain_Text64[64]={};
int main(){
int *bin;
printf("Enter 64bit Plain Text\n");
scanf("%s",plain_Text64);
bin=hexToBin(plain_Text64);
int i=0;
for(i=0;i<64;i++){
//printf("%d\n",*(bin+i));
}
printf("%d\n",binary_Plain_Text64[0]);
}
//Hex Value to Binary
int * hexToBin(char plain_Text64[]){
int k;
int hexDigitToBinary[16][4] = {{0,0,0,0}, {0,0,0,1}, {0,0,1,0}, {0,0,1,1}, {0,1,0,0}, {0,1,0,1},
{0,1,1,0}, {0,1,1,1}, {1,0,0,0}, {1,0,0,1}, {1,0,1,0}, {1,0,1,1}, {1,1,0,0}, {1,1,0,1}, {1,1,1,0}, {1,1,1,1}};
char hexDigits[16] = {'0', '1', '2', '3', '4', '5', '6', '7', '8',
'9', 'A', 'B', 'C', 'D', 'E', 'F'};
char hexadecimal[17]={};
int i,j,index=0;
strcat(hexadecimal,plain_Text64);
for(i=0; i<16; i++){
for(j = 0; j < 16; j++){
//printf("%c\t",hexadecimal[i]);
//printf("%c\n",hexDigits[j]);
if(hexadecimal[i] == hexDigits[j]){
//printf("OK\n");
for(k=0;k<4;k++){
binary_Plain_Text64[index++]= hexDigitToBinary[j][k];
}
}
}
}
return binary_Plain_Text64;
}
要在'plain_Text64 []'中存储所有16位十六进制数字,您应该至少分配16 + 1(对于字符串的NUL结尾)==>'plain_Text64 [17]'否则,您将遇到问题'的strcat(十六进制,plain_Text64);'。请用'strcpy(十六进制,plain_Text64);' –