我不确定散列表内容如何改变。散列表替换值
下面是我的代码:
public static void main(String args[]){
HashMap<String, Double> map= new HashMap<>();
map.put("com.x",30.00d);
map.put("com.y",70.00d);
map.put("com.z",70.00d);
List<String> readyServers=new ArrayList<>();
readyServers.add("system-01");
readyServers.add("system-02");
returnServerMapping(2,170.00d,map,readyServers);
}
private static void returnServerMapping(int serverRequired, double totalExpectedExecutionTime,
HashMap<String, Double> map, List<String> readyServers) {
Map<String,List<String>> testSuiteAndServerMap= new HashMap<>();
List<String> suitesForServer = new ArrayList<>();
Double executionTimePerServer = totalExpectedExecutionTime/serverRequired;
int currentServerNumber = 1;
Double currentTime = 0.0d;
for (Map.Entry<String, Double> entry : map.entrySet()) {
Double t = entry.getValue();
System.out.println(currentServerNumber + " of " + serverRequired + ": " + entry.getKey());
suitesForServer.add(entry.getKey());
System.out.println("1.suites:"+suitesForServer);
currentTime += t;
if(currentServerNumber == serverRequired){// In the last case, let's get the all remaining suites & finally map this list with the last server
}else if(currentTime >= executionTimePerServer && currentServerNumber < serverRequired){
System.out.println("Putting data into the map : server:"+readyServers.get(currentServerNumber-1)+"="+suitesForServer);
System.out.println("2.suites:"+suitesForServer);
testSuiteAndServerMap.put(readyServers.get(currentServerNumber-1), suitesForServer);
suitesForServer.removeAll(suitesForServer);
System.out.println("3.suites:"+suitesForServer);
currentServerNumber++;currentTime = 0.0d;
}
}
System.out.println("4.suites:"+suitesForServer);
testSuiteAndServerMap.put(readyServers.get(serverRequired-1), suitesForServer);
System.out.println("Final servers & suites:"+testSuiteAndServerMap);
}
和输出
1 of 2: com.z
1.suites:[com.z]
1 of 2: com.y
1.suites:[com.z, com.y]
Putting data into the map : server:system-01=[com.z, com.y]
2.suites:[com.z, com.y]
3.suites:[]
2 of 2: com.x
1.suites:[com.x]
4.suites:[com.x]
Final servers & suites:{system-01=[com.x], system-02=[com.x]}
所以现在的问题是,当系统01 = [com.z,com.y]那么怎么来它是在最后设置为system-01 = [com.x]?
编辑:调试后,我发现hashmap的内容 之前suitesForServer.removeAll(suitesForServer); => key-system-01 & value 0-com.z,value 1-com.y
after suitesForServer.removeAll(suitesForServer); => key-system-01 & value size = 0
已解决:HashMap指的是列表。一旦列表内容被改变(在任何地方),hashmap也修改了内容。为了解决这个问题,我使用了一个只拷贝列表内容的浅拷贝。
List<String> suites= new ArrayList<>(suitesForServer);
testSuiteAndServerMap.put(readyServers.get(currentServerNumber-1), suites);
调试程序。然后你就可以一步一步看到发生了什么。 – f1sh
简化了代码,并保留了您认为自己遇到问题的唯一部分。 – Ultraviolet
我相信你的问题可能与此:'currentServerNumber-1' 我可能是错的,因为我没有测试它,但从一目了然似乎可能是罪魁祸首 – DCON