每行分组日期范围

我正在尝试输出订单的每日，每周，每月和每年的计数以及这些时间范围之间这些订单的总金额。目前我已经提出了以下几点。它的很长一段时间，但它只是一个复制和粘贴的工作，同样的声明只是稍微修改，以年，月，周和日为一组。每行分组日期范围

SELECT YEAR(s.LastUpdated) AS 'Year', 0 AS 'Month', 0 AS 'Week', 0 AS 'Day', count(rowId) AS 'Transactions', ROUND(SUM(Amount),2) AS 'Partner Cut' 
FROM gfw_orders AS o 
JOIN gfw_sage_orders AS s 
ON o.sageRef = s.VendorTxCode 
WHERE YEAR(s.LastUpdated) = 2011 
GROUP BY 
YEAR(s.LastUpdated) 
    UNION 
SELECT YEAR(s.LastUpdated) AS 'Year', MONTHNAME(s.LastUpdated) AS 'Month', 0 AS 'Week', 0 AS 'Day', count(rowId) AS 'Transactions', ROUND(SUM(Amount),2) AS 'Partner Cut' 
FROM gfw_orders AS o 
JOIN gfw_sage_orders AS s 
ON o.sageRef = s.VendorTxCode 
WHERE MONTH(s.LastUpdated) = 1 
GROUP BY 
YEAR(s.LastUpdated), MONTH(s.LastUpdated) 
    UNION 
SELECT YEAR(s.LastUpdated) AS 'Year', MONTHNAME(s.LastUpdated) AS 'Month', WEEKOFYEAR(s.LastUpdated) AS 'Week', 0 AS 'Day', count(rowId) AS 'Transactions', ROUND(SUM(Amount),2) AS 'Partner Cut' 
FROM gfw_orders AS o 
JOIN gfw_sage_orders AS s 
ON o.sageRef = s.VendorTxCode 
WHERE WEEK(s.lastUpdated) = 4 
GROUP BY 
YEAR(s.LastUpdated), MONTH(s.LastUpdated), WEEK(s.LastUpdated) 
    UNION 
SELECT YEAR(s.LastUpdated) AS 'Year', MONTHNAME(s.LastUpdated) AS 'Month', WEEKOFYEAR(s.LastUpdated) AS 'Week', DAY(s.lastUpdated), count(rowId) AS 'Transactions', ROUND(SUM(Amount),2) AS 'Partner Cut' 
FROM gfw_orders AS o 
JOIN gfw_sage_orders AS s 
ON o.sageRef = s.VendorTxCode 
WHERE DAY(s.LastUpdated) = 26 
GROUP BY 
YEAR(s.LastUpdated), MONTH(s.LastUpdated), WEEK(s.LastUpdated), DAY(s.LastUpdated)

，输出

Year  Month  Week Day Count Amount 
2011 0    0  0  3  285.00 
2011 January  0  0  3  285.00 
2011 January  4  0  2  190.00 
2011 January  4  26  1  95.00

，这是提供能相应地输出的年，月，周，日数和交易金额一个理想的输出。但是，这只是一种类型的订单。在订单表中有两种类型的订单，在线和终端，理想情况下，我想在同一个查询中输出这两种类型，而不是多次查询数据库。

我有两个问题，我遇到了问题。首先，是否有一种更简单的方法来实现相同的结果？我不希望过于复杂，因为导致第二个问题，因为一些订单不同，我希望结果显示在线订单和终端订单，如果我只是复制和UNION我已经添加的' WHERE终端= 1'因为联盟结果是相同的。有没有办法在同一个查询中输出两组输出？

我很可能过分复杂化了我的目标，但事先感谢您的任何建议或指示。

来源

2011-01-26 Nathan

可以尝试像这样的例子，通过使用GROUP BY WITH ROLLUP

mysql> SELECT year, country, product, SUM(profit) 
    -> FROM sales 
    -> GROUP BY year, country, product WITH ROLLUP;

结果将是

+------+---------+------------+-------------+ 
| year | country | product | SUM(profit) | 
+------+---------+------------+-------------+ 
| 2000 | Finland | Computer |  1500 | 
| 2000 | Finland | Phone  |   100 | 
| 2000 | Finland | NULL  |  1600 | 
| 2000 | India | Calculator |   150 | 
| 2000 | India | Computer |  1200 | 
| 2000 | India | NULL  |  1350 | 
| 2000 | USA  | Calculator |   75 | 
| 2000 | USA  | Computer |  1500 | 
| 2000 | USA  | NULL  |  1575 | 
| 2000 | NULL | NULL  |  4525 | 
| 2001 | Finland | Phone  |   10 | 
| 2001 | Finland | NULL  |   10 | 
| 2001 | USA  | Calculator |   50 | 
| 2001 | USA  | Computer |  2700 | 
| 2001 | USA  | TV   |   250 | 
| 2001 | USA  | NULL  |  3000 | 
| 2001 | NULL | NULL  |  3010 | 
| NULL | NULL | NULL  |  7535 | 
+------+---------+------------+-------------+

对于Rerence与ROLLUP

您的查询是相当大的，这就是为什么我选择了放弃另一例！

来源

2011-01-26 11:23:53 Harish

每行分组日期范围

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