输入数字时出现循环错误

Question

为什么当输入数字时该循环执行3次？我只想''或'米'被接受..我怎么能解决这个问题？

cout << "Are you married or single (m/s): "; 
    cin >> status; 
    status = tolower(status); //converting to lower case 

    //validating imput for marital status 
    while((status != 'm') && (status != 's')) 
    { 
     cout << "Sorry, you must enter \"m\" or \"s\" \n" 
       << "Are you married or single (m/s): "; 
     cin >> status; 
     status = tolower(status); 
    } 

Answer 1

你的变量status可能是声明为：

char status; 

所以，cin >> status从输入读取一个单字符。但是，您可能输入了多个输入，因为输入被缓冲，您需要按Enter键。

相反，使用此声明：

string status; 

这将让输入的整条生产线，然后你可以检查行内的字符。

Answer 2

您可以使用getchar()保存到状态， 它读取缓冲区只有一个字符..

cout << "Are you married or single (m/s): "; 
    getchar(status); 

    //validating imput for marital status 
    while((status != 'm') || (status != 's')) //status can be a male OR a female 
    { 
     cout << "Sorry, you must enter \"m\" or \"s\" \n" 
       << "Are you married or single (m/s): "; 
    getchar(status); 
    }