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通过参考下面我明白多对多如何映射与关系表如何获得关系/ assosiation在sequelizejs ORM
http://sequelizejs.com/docs/latest/associations#many-to-many
User = sequelize.define('User', { user_name : Sequelize.STRING})
Project = sequelize.define('Project', { project_name : Sequelize.STRING })
UserProjects = sequelize.define('UserProjects', {
status: DataTypes.STRING
})
User.hasMany(Project, { through: UserProjects })
Project.hasMany(User, { through: UserProjects })
但是如何查询项目“一第用户
我试过像
User.find({where:{id:1},include,[UserProjects]})
User.find({where:{id:1},include,[Projects]})
User.find({where:{id:1},include,[UserProjects]})
User.find({where:{id:1},include,[Projects]})
但我不得到结果
Sequelize创建的表像下面
users(id,name)
projects(id,project_name)
userprojects(id,UserId,ProjectId)
我试图https://github.com/sequelize/sequelize/wiki/API-Reference-Associations#hasmanytarget-options
User.find({where:{id:1}}).success(function(user){
user.getProjects().success(function (projects) {
var p1 = projects[0] // this works fine but 2 queries required. I expect in single find. without getProjects
p1.userprojects.started // Is this project started yet?
})
})
如何获取一个用户的所有项目?