记录排序为：n（一对多）关系

Question

我有2个表：

+-----------+ +------------------------------------+--------------+ 
+ persons | | photos           | 
+-----------| +---------------------------------------------------+ 
+ id | name + | id | person_id | path    | title  | 
+-----------+ +---------------------------------------------------+ 
+ 1 | Tom + | 1 |   2 | ~fred/me.png  | Yo, it's Me! | 
+ 2 | Fred + | 2 |   2 | ~fred/my_wife.png | I'm Susan | 
+ 3 | Jack + | 3 |   1 | ~tom/my_dog.jpg | a woof  | 
+-----------+ +---------------------------------------------------+ 

具有在这种关系：

人的hasMany照片< - >照片属于人

我想列出所有人与他们的照片（即使有人没有一个，如杰克）和照片的顺序命名。

我应该为此编写什么SQL查询（MySQL）？我可以在一对多关系中使用连接吗？

PS：只是作为一个信息，我希望能够建立这样一个阵列中的记录：

$persons = Array(
    [0] => Array(
     [id] => 1, 
     [name] => 'Tom', 
     [Photo] => Array(
      [0] => Array(
       [id] => 3, 
       [person_id] => 1, 
       [path] => '~tom/my_dog.jpg', 
       [title] => 'a woof'    // 1st 
      ) 
     ) 
    ), 
    [1] => Array(
     [id] => 2, 
     [name] => 'Fred', 
     [Photo] => Array(
      [0] => Array(
       [id] => 2, 
       [person_id] => 2, 
       [path] => '~fred/my_wife.png', 
       [title] => "I'm Susan"   // 2nd 
      ), 
      [0] => Array(
       [id] => 1, 
       [person_id] => 2, 
       [path] => '~fred/me.png', 
       [title] => "Yo, it's Me!"  // 3rd 
      ) 
     ) 
    ), 
    [2] => Array(
     [id] => 3, 
     [name] => 'Jack', 
     [Photo] => Array() 
    ) 
) 

非常感谢！

Answer 1

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