我不断收到此错误在我的错误日志中,我不知道为什么。我看着到处Google'd,但我迷路了,我需要帮助:mysql_fetch_array()和mysql_query()问题
[Wed Mar 27 02:14:56 2013] [error] PHP Warning: mysql_query() expects parameter 2 to
be resource, null given in /nas/wp/www/cluster-1434/XXXXXXXX/wp-content/themes/mytheme
/groups/single/home.php on line 23
[Wed Mar 27 02:14:56 2013] [error] PHP Warning: mysql_fetch_array() expects
parameter
1 to be resource, null given in /nas/wp/www/cluster-1434/XXXXXXXX/wp-content/themes
/mytheme/groups/single/home.php on line 24
这是它引用的代码:
$getlatlong = mysql_query("SELECT * FROM zipcity WHERE zip='".$url[2]."'",$con);
$ll = mysql_fetch_array($getlatlong);
这是一个完整的代码,如果你需要:
<?php
global $bp;
global $current_user;
$group_name = $bp->groups->current_group->name;
$group_id = $bp->groups->current_group->id;
$groupll = groups_get_groupmeta($group_id, $meta_key = 'latlong');
$groupnamecount = strlen($group_name);
$groupcity = groups_get_groupmeta($group_id, $meta_key = 'city');
$groupstate = groups_get_groupmeta($group_id, $meta_key = 'state');
$mapaddress = $group_name.'+'.$groupcity.'+'.$groupstate;
if ($groupnamecount == '5')
{
$grouptype = "zip";
}
if ($grouptype == "zip") {
$url = explode('/',$_SERVER['REQUEST_URI']);
$zip = $url[2];
$getlatlong = mysql_query("SELECT * FROM zipcode WHERE zip='".$url[2]."'",$con);
$ll = mysql_fetch_array($getlatlong);
} else {
$groupcity = groups_get_groupmeta($group_id, $meta_key = 'city');
$groupstate = groups_get_groupmeta($group_id, $meta_key = 'state');
$mapaddress = $group_name.'+'.$groupcity.'+'.$groupstate;
}
UPDATE
问题是$ CON w ^正如在代码中声明的那样。一旦我解决了这个问题,它就完美了。感谢所有回答!
**警告**您的代码容易受到sql注入攻击! – 2013-03-27 02:35:42
我想可能是你的$ url [2]提供了空值。它可能是数组索引超出限制。你必须追加“或死(mysql_error())”到mysql_query。现在你的查询变成了mysql_query(...)或死(mysql_error())。所以你得到确切的错误。你有我的观点。 – chintan 2013-03-27 02:45:17
@ DanielA.White你能解释一下吗? – michaelrmcneill 2013-03-27 02:59:13