我想从Kafka读取数据并通过Spark RDD存储到Cassandra表中。值分裂不是(String,String)的成员
获取错误,而编译代码:
/root/cassandra-count/src/main/scala/KafkaSparkCassandra.scala:69: value split is not a member of (String, String)
[error] val lines = messages.flatMap(line => line.split(',')).map(s => (s(0).toString, s(1).toDouble,s(2).toDouble,s(3).toDouble))
[error] ^
[error] one error found
[error] (compile:compileIncremental) Compilation failed
下面的代码:当我通过互动spark-shell
手动运行该代码,它工作正常,但而错误编译代码来。
// Create direct kafka stream with brokers and topics
val topicsSet = Set[String] (kafka_topic)
val kafkaParams = Map[String, String]("metadata.broker.list" -> kafka_broker)
val messages = KafkaUtils.createDirectStream[String, String, StringDecoder, StringDecoder](ssc, kafkaParams, topicsSet)
// Create the processing logic
// Get the lines, split
val lines = messages.map(line => line.split(',')).map(s => (s(0).toString, s(1).toDouble,s(2).toDouble,s(3).toDouble))
lines.saveToCassandra("stream_poc", "US_city", SomeColumns("city_name", "jan_temp", "lat", "long"))
@RameshMaharjan:请不要格式化专有名词作为代码。卡夫卡和卡桑德拉只需要一个初始资金,就是这样 - 他们本身并不是代码。然而,像'spark-shell'这样的东西都可以,因为代码格式适合于控制台I/O(假定'spark-shell'是一个键入的命令)。 – halfer