2012-04-20 252 views
1

我想从运行在需要通过代理服务器访问外部Web服务的环境中的playframework 2应用程序调用Web服务。在我application.conf文件我已经添加了以下属性:通过HTTP代理使用WS调用Web服务

把http.proxyPort = 8000

http.proxyHost = myproxyhost.innitech.com

在我的发挥应用程序的代码,我可以访问系统属性并验证它们已被拾取。但是,在运行时,代理配置未被使用。如果我在不需要使用代理访问服务的环境中运行应用程序,则服务调用可以正常工作。

是否有可能通过代理使用播放框架调用Web服务,如果是这样,如何?

这里是调用的例子:

def watched(username: String, password: String): Promise[Seq[Repo]] = { 
    val promiseResponse = WS.url(baseUrl + "/user/watched") 
    .withAuth(username, password, com.ning.http.client.Realm.AuthScheme.BASIC) 
    .get 

    promiseResponse.map(_.json.as[Seq[Repo]]) 
} 

以下堆栈跟踪代表什么,我在运行时看到:

play.core.ActionInvoker$$anonfun$receive$1$$anon$1: Execution exception [[Connec 
tException: https://api.github.com/user]] 
    at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:82) [p 
lay_2.9.1.jar:2.0] 
    at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:63) [p 
lay_2.9.1.jar:2.0] 
    at akka.actor.Actor$class.apply(Actor.scala:290) [akka-actor.jar:2.0] 
    at play.core.ActionInvoker.apply(Invoker.scala:61) [play_2.9.1.jar:2.0] 
    at akka.actor.ActorCell.invoke(ActorCell.scala:617) [akka-actor.jar:2.0] 

    at akka.dispatch.Mailbox.processMailbox(Mailbox.scala:179) [akka-actor.jar:2.0] 
Caused by: java.net.ConnectException: https://api.github.com/user 
    at com.ning.http.client.providers.netty.NettyConnectListener.operationCo 
mplete(NettyConnectListener.java:100) ~[async-http-client.jar:na] 
    at org.jboss.netty.channel.DefaultChannelFuture.notifyListener(DefaultCh 
annelFuture.java:397) ~[netty.jar:na] 
    at org.jboss.netty.channel.DefaultChannelFuture.addListener(DefaultChann 
elFuture.java:143) ~[netty.jar:na] 
    at com.ning.http.client.providers.netty.NettyAsyncHttpProvider.doConnect 
(NettyAsyncHttpProvider.java:1004) ~[async-http-client.jar:na] 
    at com.ning.http.client.providers.netty.NettyAsyncHttpProvider.execute(N 
ettyAsyncHttpProvider.java:829) ~[async-http-client.jar:na] 
    at com.ning.http.client.AsyncHttpClient.executeRequest(AsyncHttpClient.j 
ava:499) ~[async-http-client.jar:na] 
Caused by: java.nio.channels.UnresolvedAddressException: null 
    at sun.nio.ch.Net.checkAddress(Net.java:30) ~[na:1.6.0_25] 
    at sun.nio.ch.SocketChannelImpl.connect(SocketChannelImpl.java:480) ~[na 
:1.6.0_25] 
    at org.jboss.netty.channel.socket.nio.NioClientSocketPipelineSink.connec 
t(NioClientSocketPipelineSink.java:142) ~[netty.jar:na] 
    at org.jboss.netty.channel.socket.nio.NioClientSocketPipelineSink.eventS 
unk(NioClientSocketPipelineSink.java:105) ~[netty.jar:na] 
    at org.jboss.netty.handler.ssl.SslHandler.handleDownstream(SslHandler.ja 
va:459) ~[netty.jar:na] 
    at org.jboss.netty.handler.codec.oneone.OneToOneEncoder.handleDownstream 
(OneToOneEncoder.java:55) ~[netty.jar:na] 
+0

查看Play源代码,http客户端在没有任何上下文的情况下被实例化,例如, lazy val client = new AsyncHttpClient()。我相信AsyncHttpClientConfig需要使用适当的代理上下文构建,然后作为构造函数参数传递给AsynchHttpClient,以正确初始化客户端以通过代理。 – 2012-04-25 03:01:30

回答

2

在GitHub上的当前快照应该可以解决这个问题,因为它建立使用Play上下文的AsyncHttpClientConfig,然后使用配置初始化AsynchHttpClient:

lazy val client = { 
    import play.api.Play.current 
    val config = new AsyncHttpClientConfig.Builder()  
    .setConnectionTimeoutInMs(current.configuration.getMilliseconds("ws.timeout").getOrElse(120000L).toInt) 
    .setFollowRedirects(current.configuration.getBoolean("ws.followRedirects").getOrElse(true)) 
    .setUseProxyProperties(current.configuration.getBoolean("ws.useProxyProperties").getOrElse(true)) 

    current.configuration.getString("ws.useragent").map { useragent => 
    config.setUserAgent(useragent) 
} 
new AsyncHttpClient(config.build()) 

}

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