我在将数据插入数据库'justrated'时遇到问题。一旦用户输入了他们的商业名称,它应该在“商业”表中创建一个新条目。出于某种原因,我无法得到它,以便数据输入到表格中。任何建议很乐意欣赏。将数据插入MYSQL数据库
CODE:
<!DOCTYPE html>
<html>
<head>
<title>Test</title>
</head>
<body>
<form>
<input type="text" name="BusinessName" method="POST">
<input type="Submit" value="submit" name="submit" method="POST">
</form>
<?php
if (isset($_POST["submit"])){
//create connection
$conn = new mysqli("localhost", "root", "", "justrated");
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO businesses (BusinessName)
VALUES ('".$_POST['BusinessName']."')";
mysql_query($sql);
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
}
?>
</body>
</html>
您需要学习[html form](http://www.w3schools.com/html/html_forms.asp)。并且不要混合使用'mysql和mysqli' – Saty
当你使用'mysqli'时,你不能使用'mysql_query()'。 – Barmar
@Saty他的表格有什么问题? – Barmar