我有一个配方表和配料表,两个表的主键都是自动增量,配方的主键是配料中的外键。我将数据从html发布到php。请注意,我的成分文本框是动态生成的,并成功将数据发布到php脚本。发布的数据是正确的,当我插入这个数据表我的查询工作正常,但数据不会添加到MySQL表。我的代码和输出是插入查询不会插入数据到mysql数据库表
$sql = "insert into recipe (rec_id, Name, Overview,category, Time, Image) values ('', '$name','$overview','$category','$time','$TARGET_PATH')";
$result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error());
$rec_id = mysql_insert_id();
和成分
$ingredient = $_POST['ingredient'];
$amount = $_POST['amount'];
$integer = 0;
while (count($ingredient)>$integer) {
if (($ingredient[$integer] <> "") && ($amount[$integer] <> "")){
$sql = "INSERT INTO `cafe`.`ingredients` (`ingredient_id`, `ingredient_name`, `ammount`, `rec_id`,)
VALUES ('', '".$ingredient[$integer]."', '".$amount[$integer]."', '$rec_id')";
mysql_query($sql);
echo $sql."
";
}
else{
echo "ingredient number ".($integer+1)." is missing values and cannot be inserted.";
}
$integer = ($integer + 1);
}
当我附和了把查询是
nsert into recipe (rec_id, Name, Overview,category, Time, Image) values ('', 'demo recipe','no overview','meal','10/12/10 : 13:02:33','http://www.localhost/cafe/pics/demo.gif')
INSERT INTO cafe
.ingredients
(ingredient_id
, ingredient_name
, ammount
, rec_id
,) VALUES ('', 'ingredient one', '3gm', '29')
INSERT INTO cafe
.ingredients
(ingredient_id
, ingredient_name
, ammount
, rec_id
,) VALUES ('', 'ingredient two', '3gm', '29')
INSERT INTO cafe
.ingredients
(ingredient_id
, ingredient_name
, ammount
, rec_id
,) VALUES ('', 'ingredient three', '3gm', '29')
,但是当我从成分看mysql表或retriew数据有成分中没有数据。
删除
cafe
你可以请张贴的配方和成分的定义表? – 2010-12-10 08:24:50`amount`拼写`amount` – 2010-12-10 08:46:58