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我有一个表格,将数据插入数据库。其中一个字段是weDate
这与PHP mysql_query()手动输入日期的作品PHP变量不
$weDate=date('Y-m-d',strtotime('Friday'))
填写如果我使用以下命令:
$sql = mysql_query("SELECT ID as 'DB_ID',
partnumber as 'Part_Number',
pndesc as 'Part Number Description',
name as 'Name',
reason as 'Reason',
comment as 'Comments',
date as 'Date',
time as 'Time',
weDate as 'Weekend Date'
FROM $table
WHERE weDate = '2013-05-03'");
我得到的返回结果。
当我尝试:
$sql = mysql_query("SELECT ID as 'DB_ID',
partnumber as 'Part_Number',
pndesc as 'Part Number Description',
name as 'Name',
reason as 'Reason',
comment as 'Comments',
date as 'Date',
time as 'Time',
weDate as 'Weekend Date'
FROM $table
WHERE weDate = '$weDate2'");
我得不到任何回报。为什么?
的PHP变量是:
$weDate2 = date('Y-m-d', strtotime('-1 weeks Friday')
[**请不要在新代码中使用'mysql_ *'函数**](http://bit.ly/phpmsql)。他们不再被维护[并且被正式弃用](http://j.mp/XqV7Lp)。看到[**红框**](http://j.mp/Te9zIL)?学习[*准备的语句*](http://j.mp/T9hLWi),并使用[PDO](http://php.net/pdo)或[MySQLi](http://php.net/ mysqli) - [这篇文章](http://j.mp/QEx8IB)将帮助你决定哪个。如果你选择PDO,[这里是一个很好的教程](http://j.mp/PoWehJ)。 – Kermit 2013-05-06 19:00:00
您指的是哪个星期五?如果你运行'date('Y-m-d',strtotime('Friday'))',你会得到'2013-05-10'。 – Terry 2013-05-06 19:00:12
您是否尝试回显$ weDate2以查看实际输出的内容?我敢打赌,问题在于它实际上在输出什么,而不是你期望它输出什么。 – 2013-05-06 19:01:01