卷曲的libcurl HTTP JSON格式放置请求

Question

目前我正在写一个程序与ArangoDB

互动有什么办法使用libcurl的JSON格式发送HTTP PUT请求？

我在卷曲当前命令是

curl -X PUT --data-binary @- --dump - --user "root:" http://localhost:8529/_db/myapp1/_api/simple/lookup-by-keys << EOF {"keys" : [ "FirstUser" ], "collection" : "five"} EOF 

我想知道等价的libcurl代码发送上述请求。谢谢

Answer 1

//PUT Request 
#include <stdio.h> 
#include <string.h> 
#include <curl/curl.h> 

int main(int argc, char const *argv[]){ 
CURL *curl; 
CURLcode res; 
long http_code; 
static const char *jsonObj = //insert json here 

curl = curl_easy_init(); 
curl_global_init(CURL_GLOBAL_ALL); 

if(curl){ 

    curl_easy_setopt(curl, CURLOPT_URL, "//insert your url here"); 
    curl_easy_setopt(curl, CURLOPT_HTTPAUTH, (long)CURLAUTH_BASIC); 
    curl_easy_setopt(curl, CURLOPT_USERPWD, "root:"); 

    curl_easy_setopt(curl, CURLOPT_CUSTOMREQUEST, "PUT"); 
    curl_easy_setopt(curl, CURLOPT_POSTFIELDS, jsonObj); 


    //enable to spit out information for debugging 
    //curl_easy_setopt(curl, CURLOPT_VERBOSE,1L); 

    res = curl_easy_perform(curl); 

    if (res != CURLE_OK){ 
     fprintf(stderr, "curl_easy_perform() failed: %s\n", curl_easy_strerror(res)); 
    } 

    printf("\nget http return code\n"); 
    curl_easy_getinfo(curl, CURLINFO_RESPONSE_CODE, &http_code); 
    printf("http code: %lu\n", http_code); 


    curl_easy_cleanup(curl); 
    curl_global_cleanup(); 

    } 
return 0; 
} 

这是我想出的解决方案。请随时添加/改进