行合并2008

Question

我有一个表像下面这样：

 
Customer |Type  |Count 
Joe  |Silver-S |1 
Joe  |Silver |7 
Joe  |Gold  |3 
Joe  |Gold-S |2 

我需要合并这使它看起来像下面这样：

 
Customer |Type  |Count 
Joe  |Silver |8 
Joe  |Gold  |5 

帮助！

Answer 1

select Customer, 
case when Type like 'Silver%' then 'Silver' 
when Type like 'Gold%' then 'Gold' end, sum(Count) 
    from table 
    group by Customer, 
case when Type like 'Silver%' then 'Silver' 
when Type like 'Gold%' then 'Gold' end 

Answer 2

select Customer, [Type], SUM([Count]) from (
    select Customer, replace([Type], '-S', '') [Type], [COUNT] from Customer 
) 
t 
group by customer, [Type] 

Answer 3

试试这个：

select 
    Customer, 
    left([Type],CHARINDEX('-', [type])), 
    sum(COUNT) 

from Customers 

group by 
    Customer, 
    left([Type],CHARINDEX('-', [type])); 

或者这样：//编辑：这可能是慢

select 
     Customer, 
     replace([Type], '-S', ''), 
     sum(COUNT) 

    from Customers 

    group by 
     Customer, 
     replace([Type], '-S', ''); 

如果你的数据库项目 - 你应该重新设计数据库并将该“-S”放在另一个字段中，或避免将来出现这种情况。

Answer 4

我认为在这种情况下使用cte更清洁。我会做这样的事情：

首先，测试数据：

DECLARE @tbl TABLE(Customer VARCHAR(100),[Type] VARCHAR(10),[Count] INT) 

INSERT INTO @tbl 
VALUES 
    ('Joe','Silver-S',1), 
    ('Joe','Silver',7), 
    ('Joe','Gold',3), 
    ('Joe','Gold-S',2) 

的查询：

;WITH CTE AS 
(
    SELECT 
     tbl.Customer, 
     REPLACE(tbl.[Type],'-S','') AS [Type], 
     tbl.[Count] 
    FROM 
     @tbl AS tbl 
) 
SELECT 
    CTE.Customer, 
    CTE.[Type], 
    SUM(cte.[Count]) AS [Count] 
FROM 
    CTE 
GROUP BY 
    CTE.Customer, 
    CTE.[Type] 

Answer 5

下面是一个使用分区的办法解决：

SELECT DISTINCT Customer, REPLACE([Type], '-S', '') AS [Type], 
SUM([Count]) OVER (PARTITION BY (SELECT REPLACE([Type], '-S', ''))) AS [Count] 
FROM Customer