我怎么能让Math.random（）在每次调用存储在其中的变量时都返回不同的值？

Question

我现在有一项任务，它要求我使用Math.random()保存在一个变量中，我已经命名为randomNumberBetween0and5（它实际上是Math.floor((Math.random() * 5) + 0);，它返回一个介于0和5之间的数字。我使用这个数字来指代其他地方某些数组的索引）我在代码中多次调用它两次，但是我需要Math.random()只执行一次，然后将它的值存储在randomNumberBetween0and5变量中以备后用，而不会更改，如果我再次调用变量两次或三次。

我试图将randomNumberBetween0and5的值存储在另一个变量中，并且（如预期的那样）并不能帮助解决问题。任何帮助肯定会感激！谢谢！

（这里的一切都只是在案件的代码，你想看到它。）

var names = ["Lázaro", "Aviram", "Samuel", "Miles", "Felix"]; // Defining an array of random names 
var people = []; // Declaring the array to hold each instance of the 'Person' object 

// For() to create one new instance thrice for three names of the 'names' array in the 'Person' object defined in 'person.js' 

for (var i=0;i < 3;i++) { 
    var randomNumberBetween0and5 = Math.floor((Math.random() * 5) + 0); // Randomly choosing a number for the arrays to be passed to the 'Person()' object's methods defined in 'person.js' 
    var newInstance = new Person.generate(names.splice(randomNumberBetween0and5,randomNumberBetween0and5+1),Person.actions[randomNumberBetween0and5],Person.jobs[randomNumberBetween0and5],i+1); // Creating a new instance of the 'Person()' object and passing a random name, action (from the Person object's properties), and job (also from the Person object's properties), along with the current loop number for the row to use (i begins at 0 so it becomes 1,2,3 instead of 0,1,2 when a 1 is added) 
    //people.push(newInstance); // Adding the new instance to the 'people' array of instances 
    people.push(newInstance); // Adding the newly created instance of 'Person' to the variable 'people' 
}; // Ending the for() 

console.log(people); // Logging the 'people' array for debugging 
console.log("Main.js has been completely interpreted -- Nothing has broken yet."); // Reassuring console log to state that this file has completely executed without breaking 

Answer 1

也许这个段解释了它：

// When Math.floor is initially called it creates the random number 
// store this in variable: randomNumberBetween0and5 
var randomNumberBetween0and5 = Math.floor((Math.random() * 5) + 0); 

for (var i = 0; i < 10; i++) { 
    // randomNumberBetween0and5 will never change in this function 
    console.log(randomNumberBetween0and5); 
} 

问题在你的代码是你在循环中调用Math.floor。这将始终创建一个随机。

与您的代码试试这个：

var names = ["Lázaro", "Aviram", "Samuel", "Miles", "Felix"]; 
var people = []; 
var randomNumberBetween0and5 = Math.floor((Math.random() * 5) + 0); 

for (var i=0;i < 3;i++) { 
    console.log('randomNumberBetween0and5 is: ' + randomNumberBetween0and5); 
    var newInstance = new Person.generate(names.splice(randomNumberBetween0and5,randomNumberBetween0and5+1),Person.actions[randomNumberBetween0and5],Person.jobs[randomNumberBetween0and5],i+1); 
    people.push(newInstance); 
}; 

Answer 2

它是好的，如果你让randomNumberBetween0and5阵列，使得它能够同时存储3个不同的数字？

var randomNumberBetween0and5 = []; 
for(var i = 0; i < 3; i++){ 
    randomNumberBetween0and5.push(Math.floor(Math.random()*5)); 
    //do stuff with randomNumberBetween0and5[i] 
} 

Answer 3

FYI的Math.random（）返回0和1之间的数字由5乘以你之间的一个数字0和5.您需要Math.round（的Math.random（）* 5）正确设置你的变量。只要Math.random返回1，Math.floor只会让你得到5，我不相信会这样。