MySQL查询使用子查询两次

我有这个疑问MySQL查询使用子查询两次

SELECT itemID, locationParentID, locationID, categoryParentID, categoryID, itemTitle, itemDetails, itemAttributes, itemPictures, itemFeatured, itemSpotlight, itemAdded 
FROM items 
WHERE locationID NOT IN 
    (SELECT locationID 
    FROM sites_locations 
    WHERE siteID != 2) AND items.siteID IN('1,2') AND itemStatus = '1' 
    AND itemAdded > '1356048000'

，它工作正常，但是当我执行此查询失败

SELECT itemID, locationParentID, locationID, categoryParentID, categoryID, 
itemTitle, itemDetails, itemAttributes, itemPictures, itemFeatured, itemSpotlight, itemAdded FROM items 
WHERE locationID NOT IN 
    (SELECT locationID 
    FROM sites_locations WHERE siteID != 2) 
    AND categoryID NOT IN (SELECT categoryID FROM sites_categories 
    WHERE siteID != 2) AND items.siteID IN('1,2') AND itemStatus = '1' 
    AND itemAdded > '1356048000'

这里的区别是我加入的条款

AND categoryID NOT IN(SELECT categoryID FROM sites_categories 
WHERE siteID != ".$cfg['site']['siteID'].")

任何想法，为什么这不起作用？

甚至更好，加入查询来帮助优化它。对于sites_categories

表结构中，数据以 enter image description here

物品表结构，数据是在 enter image description here

表结构sites_locations enter image description here

为位置表结构，数据是在 enter image description here

在此先感谢。

来源

2013-02-22 Ian Wilkinson

什么是不工作相关的一些错误或列名？ – 2013-02-22 03:10:18

你能不能替换内部加入] – 2013-02-22 03:12:38

我不知道如何 – 2013-02-22 03:13:02

试试这个

SELECT i.itemID, i.locationParentID, i.locationID, i.categoryParentID, i.categoryID, 
i.itemTitle, i.itemDetails, i.itemAttributes, i.itemPictures, i.itemFeatured, i.itemSpotlight, i.itemAdded 
FROM items i, sites_locations sl, sites_categories sc 
WHERE i.locationID = sl.locationID 
AND i.categoryID = sc.categoryID 
AND i.siteID = 1 AND i.itemStatus = '1' 
AND i.itemAdded > '1356048000'

它可能有错误的PL纠正这些错误

来源

2013-02-22 03:50:28 Meherzad

@IanWilkinson您已保存您的$ 20;）： P – Meherzad 2013-02-22 04:23:34

你可以把它变成像加入这样：

SELECT i.itemID, i.locationParentID, i.locationID, i.categoryParentID, i.categoryID, 
     i.itemTitle, i.itemDetails, i.itemAttributes, i.itemPictures, i.itemFeatured, 
     i.itemSpotlight, i.itemAdded 
FROM items i left outer join 
    sites_locations sl 
    on i.locationID = sl.locationId and sl.siteId <> 2 left outer join 
    sites_categories sc 
    on i.categoryID = sc.categoryId and sc.siteId <> 2 
WHERE sl.locationID is NULL and sc.categoryId is NULL and 
     i.siteID IN (1, 2) AND i.itemStatus = 1 AND i.itemAdded > 1356048000

这也可能有较好表现。

注意：我没有测试过这个SQL，因此它可能有语法错误。特别是，您可能需要在某些列名之前添加别名（最好在列名之前始终使用别名）。

来源

2013-02-22 03:25:42

没有，仍然没有工作，我会弄乱它，看看我能否得到它，如果我得到它与您的代码工作我是一个我的话，20美元将标题你的方式:) – 2013-02-22 03:29:13

解决方案SELECT itemID，locationParentID，locationID，categoryParentID，categoryID，itemTitle，itemDetails，itemAttributes，itemPictures，itemFeatured，itemSpotlight，itemAdded从项目WHERE items.siteID IN（'1,2'）AND items.locationID =（SELECT locationID FROM sites_locations sl WHERE sl.locationID = items.locationID AND siteID ='2'）AND items.categoryID =（选择categoryID FROM sites_categories sc WHERE sc.categoryID = items.categoryID AND siteID ='2'）AND itemStatus ='1'且itemAdded>'1356048000'ORDER BY itemID DESC LIMIT 15 – 2013-02-22 03:53:25

解决

SELECT itemID, locationParentID, locationID, categoryParentID, categoryID, itemTitle, itemDetails, itemAttributes, itemPictures, itemFeatured, itemSpotlight, itemAdded FROM items WHERE items.siteID IN('1,2') AND items.locationID = (SELECT locationID FROM sites_locations sl WHERE sl.locationID = items.locationID AND siteID = '2') AND items.categoryID = (SELECT categoryID FROM sites_categories sc WHERE sc.categoryID = items.categoryID AND siteID = '2') AND itemStatus = '1' AND itemAdded > '1356048000' ORDER BY itemID DESC LIMIT 15

来源

2013-02-22 03:54:27

MySQL查询使用子查询两次

回答

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