我无法让我的计算器工作。当我运行它时,它说y elif语句是无效的,函数在这个clode块之上,它应该工作。我的python计算器给出了一个无效的语法错误
choice = raw_input("chose an operator [1,2,3,4]")
num1 = raw_input("input number 1")
num2 = raw_input("input number 2")
if choice == 1:
print(num1,"+",num2,"=",add(num1,num2)
elif choice == 2:
print(num1,"-",num2,"=",minus(num1,num2)
elif choice == 3:
print(num1,"x",num2,"=",times(num1,num2)
elif choice == 4:
print(num1,"/",num2,"=",divide(num1,num2)
else:
print("that's not a valid operator")
,这里是我的错误
File "calculator.py", line 27
elif choice == 2:
你错过了一个')''中的每elif''print'后。它应该是'print(num1,“+”,num2,“=”,add(num1,num2)),而不是print(num1,“+”,num2,“=”,add(num1,num2) ' –
你错过了最后一个'''除最后一个 – 2015-10-17 19:28:56
以外,如果你使用Python 2.x,你需要在if语句中的每个数字周围放置''“'if if choice ==”1 “'因为raw_input告诉它是一个字符串 – 2015-10-17 19:31:30