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我有以下形式:基于通过复选框获取的表将数据存储在SQL中?
<!DOCTYPE html>
<html>
<head>
<title>Update Notifications</title>
</head>
<body>
<form enctype="multipart/form-data" action="update1.php" method="post">
<fieldset>
<legend>Enter Date and Notification, select the requisite categories</legend>
HOD<input type="checkbox" name="update[]" id="update" value="ihod"><br>
CR<input type="checkbox" name="update[]" id="update" value="icr"><br>
Non Teaching Staff<input type="checkbox" name="update[]" id="update" value="intstaff"><br>
Teaching Staff<input type="checkbox" name="update[]" id="update" value="itstaff"><br>
FE<input type="checkbox" name="update[]" id="update" value="ife"><br>
SE IT<input type="checkbox" name="update[]" id="update" value="iseit"><br>
SE EXTC<input type="checkbox" name="update[]" id="update" value="iseextc"><br>
SE COMPS<input type="checkbox" name="update[]" id="update" value="isecomp"><br>
TE IT<input type="checkbox" name="update[]" id="update" value="iteit"><br>
TE EXTC<input type="checkbox" name="update[]" id="update" value="iteextc"><br>
TE COMPS<input type="checkbox" name="update[]" id="update" value="itecomp"><br>
BE IT<input type="checkbox" name="update[]" id="update" value="ibeit"><br>
BE EXTC<input type="checkbox" name="update[]" id="update" value="ibeextc"><br>
BE COMPS<input type="checkbox" name="update[]" id="update" value="ibecomp"><br>
Notification: <input type="file" name="photo"><br>
Date: <input type="text" name="date"><br>
<input type="submit" name="Submit">
</fieldset>
</form>
</body>
</html>
我update1.php包含以下代码:
<?php
if (isset($_POST['table']) && isset($_POST['date']) && isset($_POST['pic']) && isset($_POST['target'])){
$target = "notifications/"; //This is the directory where images will be saved
$target = $target . basename($_FILES['photo']['name']);
$date=$_POST['date'];
$pic=($_FILES['photo']['name']);
mysql_connect("127.0.0.1", "root", "") or die(mysql_error()) ;
mysql_select_db("login") or die(mysql_error()) ;
foreach ($_POST[$name] as $update) {
if($update == $value){
$table = $_POST[$name];
mysql_query("INSERT INTO `$table` VALUES ('$date', '$pic')") ;
if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) {
echo "The file ". basename($_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";
}
else {
echo "Sorry, there was a problem uploading your file."; }
}
}
}
我想要做的是把数据存储进表(这已经在创建“登录”数据库的名称与复选框值相对应)。勾选复选框后,我希望程序自动更新具有必要值(即日期和文件名)的相应表格。我目前困惑于foreach()语法以及它如何工作。另外,可以使用implode来达到这个目的吗?
PS:是否可以使用表单中的标记接受值,并使用以下方法将其存储到数据库中?
重复的问题请看看这个http://stackoverflow.com/q/4997252/3293985 – TheSk8rJesus 2015-04-01 21:13:08
@ TheSk8rJesus我仍然与SQL实现混淆。我仍然无法根据html表单中的值接受单独的表名,然后将值存储在其中。 – 2015-04-02 05:25:05