PHP的MySQL的公告列表卡住

-1

ID | Name 
1 | Job 
9 | Property 
11 | General

bx_ads_category_subs（子分类表）

ID | IDClassified | NameSub 
85 | 1   | Developer 
86 | 1   | Accountant 
87 | 9   | For Sale 
88 | 11   | For Rent

bx_ads_main（公告目录表）

ID | IDClassifiedsSubs | Subject | etc. 
10 | 85    | A Company need Php Developer 
11 | 85    | B Company need Php Developer 
12 | 86    | C Company need Accountant 
13 | 88    | Lux Apartment

我需要列表像那样

SELECT * FROM bx_ads_category WHERE ID = 1

结果

10 = A Company need Php Developer 
11 = B Company need Php Developer 
12 = C Company need Accountant

来源

2014-02-16 user3302707

什么问题？你能更具体地说明你需要什么吗？ – malta

我们读心术...我用心灵感应也得到了答案，现在... – CommandZ

我不能像上市10 = A公司需要PHP开发人员 11 = B公司需要PHP开发我需要我可以用什么，像这样的列表“SELECT * FROM bx_ads_category WHERE ID = 1” – user3302707

SELECT m.id, m.subject 
    FROM bx_ads_main m JOIN bx_ads_category_subs s 
    ON m.IDClassifiedsSubs = s.ID JOIN bx_ads_category c 
    ON s.IDClassified = c.ID 
WHERE c.ID = 1

输出：

 
| ID |      SUBJECT | 
|----|------------------------------| 
| 10 | A Company need Php Developer | 
| 11 | B Company need Php Developer | 
| 12 | C Company need Accountant |

这里是SQLFiddle演示

来源

2014-02-16 22:57:25 peterm

它的工作完美，谢谢。 – user3302707

我想你可以有你的结果与联接查询如下

SELECT * 
FROM bx_ads_category a 
INNER JOIN bx_ads_main b 
ON a.IDClassifiedsSubs = b.ID 
INNER JOIN bx_ads_category c 
ON b.IDClassified = c.ID 
WHERE c.ID = 1

来源

2014-02-16 22:46:03 Fabio

PHP的MySQL的公告列表卡住

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