SQL平稳度计算排序日期

第一个表Amountin样子：

AmountIn

+--------+--------------+-----------+ 
| account| date   | AmountIn | 
+--------+--------------+-----------+ 
| A  | 2017/2/6 | 200  | 
| A  | 2017/2/5 | 100  | 
| A  | 2017/2/5 | 500  | 
| B  | 2017/2/1 | 1000  | 
| B  | 2017/2/1 | 2000  | 
| C  | 2017/1/20 | 25  | 
+--------+----+---------+-----------+

，第二个看起来像：

AmountOut

+--------+--------------+-----------+ 
| account| date   |AmountOut | 
+--------+--------------+-----------+ 
| A  | 2017/2/8 | 200  | 
| A  | 2017/2/7 | 100  | 
| A  | 2017/2/6 | 500  | 
| B  | 2017/2/2 | 1000  | 
| B  | 2017/2/1 | 2000  | 
| C  | 2017/1/20 | 25  | 
+--------+----+---------+-----------+

现在我想一个查询，显示结果如下： ForAccountA

+--------+--------------+----------+-----------+------------+ 
| account| date   | AmountIn | AmountOut | Balancy | 
+--------+--------------+-------- -+-----------+------------+ 
| A  | 2017/2/8 | 0  | 200  | 0   | 
| A  | 2017/2/7 | 0  | 100  | 200  | 
| A  | 2017/2/6 | 200  | 0   | 300  | 
| A  | 2017/2/6 | 0  | 500  | 100  | 
| A  | 2017/2/5 | 100  | 0   | 600  | 
| A  | 2017/2/5 | 500  | 0   | 500  | 
+--------+----+---------+----------+-----------+------------+

这意味着工会表和计算balancy为：

last balance + AmountIn - AmounOut

我的代码是：

select 
    t.*, 
    @sum := if(@account = account, 
       @sum + AmountIn - AmountOut, 
       if((@account := account) is not null, 
        AmountIn - AmountOut, 0) 
      ) balance 
from (
    select 
     * 
    from (
     select 
      1 x, 
      account, 
      date, 
      AmountIn, 
      0 AmountOut 
     from AmountIn 
     union all 
     select 
      0 x, 
      account, 
      date, 
      0 AmountIn, 
      AmountOut 
     from AmountOut 
    ) t order by account, date, x 
) t cross join (select @account := null, @sum := 0) t2

但它给我造成的时间升序我希望它被订购按日期递减。我neet o看到上面的最后操作，否则当数据得到一个我将很难o向下滚动或转到下一页请帮助

来源

2017-02-22 Yahia Baiba

'按帐户牛逼顺序，日期降序，x' – litelite

在这种情况下，'balanacy'会变得乱七八糟，不正确 –

基于非标准语法添加'mysql'标签 –

这是一个解决方案，由txn建立的txn平衡。我用unionall（不参加）构建初始表作为你的榜样好像你不想与这两个amountin和amountout行：

select * 
from (
select 
@cnt := If(@prev=account , @cnt+1,1) rown, a.*, 
@balance := if( @prev=account, @balance + amountin - amountout, amountin - amountout) balance,               
@prev := account prev from 
(select account, date, amountin, 0 amountout from amountin 
union all 
select account, date, 0, amountout from amountout) a, (select @cnt := 1) b, (select @prev :='') c, (select @balance :=0) bal 
order by account, date 
    ) r 
    order by account, rown desc, date desc

Here is a working exmaple with your data

来源

2017-02-22 17:12:36 EoinS

这是完美而美丽的，非常感谢，如果表格是3，我们添加另一个表'thirdTable'表示'balance = lastbalance + amountin + thirdamount-amountout'第三个表与其他表具有相同的结构 –

再次感谢你，对于迟到的+1抱歉，我会感激如果可以给如何会像 –

SQL平稳度计算排序日期

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